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Soloha48 [4]
3 years ago
13

Suppose that you toss a rock upward so that it rises and then falls back to the earth. If the acceleration due to gravity is 9.8

m/sec2,
what is the rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero)?
Assume that air resistance is negligible.

A)The acceleration of the rock is zero.
B)The rock has an upward acceleration of 19.6 m/s2.
C)The rock has a downward acceleration of 19.6 m/s2.
D)The rock has a downward acceleration of 9.8 m/s2.
E)The rock has an upward acceleration of 9.8 m/s2.
Physics
1 answer:
arsen [322]3 years ago
3 0
"The rock has a downward acceleration of 9.8 m/s2" is the one among the following choices that explains the <span>rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero). The correct option among all the options that are given in the question is option "D". </span>
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Explanation:

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If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________
siniylev [52]

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

V_e=\sqrt{\dfrac{2GM}{r}}

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

V_e=\sqrt{\dfrac{2GM}{r\times 2}}

V_e = \sqrt{\dfrac{GM}{r}}.

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

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8 0
1 year ago
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Ede4ka [16]

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2 years ago
What is the molar mass of an ideal gas if a 0.800 g sample of this gas occupies a volume of 200. mL at 50.0 oC and 720. mm Hg?
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PV=nRT
(720/760)(0.200)=(0.800/x)(0.08206)(323.15)
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3 years ago
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