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Soloha48 [4]
3 years ago
13

Suppose that you toss a rock upward so that it rises and then falls back to the earth. If the acceleration due to gravity is 9.8

m/sec2,
what is the rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero)?
Assume that air resistance is negligible.

A)The acceleration of the rock is zero.
B)The rock has an upward acceleration of 19.6 m/s2.
C)The rock has a downward acceleration of 19.6 m/s2.
D)The rock has a downward acceleration of 9.8 m/s2.
E)The rock has an upward acceleration of 9.8 m/s2.
Physics
1 answer:
arsen [322]3 years ago
3 0
"The rock has a downward acceleration of 9.8 m/s2" is the one among the following choices that explains the <span>rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero). The correct option among all the options that are given in the question is option "D". </span>
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A bucket weighing 5 lbs is lifted at a constant rate from the bottom of a 100 ft well by a rope which weighs 5 lbs. The bucket h
8_murik_8 [283]

Answer:

W_{bucket} = 24934.85\,lbf\cdot ft

Explanation:

The system is modelled after the Principle of Energy Conservation and the Work-Energy Theorem:

W_{bucket} = U_{g,B, bucket} - U_{g,A,bucket} +U_{g, B, water}-U_{g,A,water} +U_{g, B, rope} -U_{g,A,rope}

W_{bucket} = (5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-0\,ft) + (25\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft) - (30\,lb)\cdot (32.174\,\frac{ft}{s^{2}})\cdot (0\,ft)+(5\,lb) (32.174\,\frac{ft}{s^{2}})\cdot (100\,ft-50\,ft)

W_{bucket} = 24934.85\,lbf\cdot ft

6 0
4 years ago
If a 4 engine jet accelerates down a runway at 8.7 m/s^2, Suppose now that all 4 engins are operational on the jet from the prev
soldi70 [24.7K]

Answer:

5.22m/s^2

Explanation:

One of the first propulsion characteristics given in the example is that all engines are equal.

In this way if we have 4 engines running at the same time, it means that its capacity is 100%.

Under this premise, if 100% is found, the Jet is capable of reaching a speed of 8.7m / s ^ 2.

However, the question is, what would happen if 2.4 "Engines" now work.

To do this then we make a simple equivalence,

If 4 engines is the equivalent of 100%, when would it be 2.4 engines?

X = \frac{2.4 * 100\%} { 4 }= 60\%

In this way it would mean that the body could be driven to 60% of its total.

So

Speed_{Decreased} = 8.7 * 60\% = 5.22 \frac{m}{s^2}

3 0
3 years ago
Please help with this problem.
pochemuha

Answer:

its Y because the dot that represents it is close to S

6 0
4 years ago
Which microscope is used to see internal structures of cells in a natural state? darkfield microscope phase-contrast microscope
harkovskaia [24]

Answer:

Phase contrast microscope

Explanation:

It is used for viewing biological structures not visible under the microscope. It is used for viewing microrganisms live

8 0
4 years ago
Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl
o-na [289]

Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

F=ma

100=100m\times a

ma=1\ N

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

F_{100-99}=ma

F_{100-99}=1

We need to calculate the total number of masses attached to the string

Using formula for mass

m'=(100-50)m

m'=50m

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

F_{50}=m'a

Put the value into the formula

F_{50}=50m\times a

F_{50}=50\times1

F_{50}=50\ N

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

8 0
4 years ago
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