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Soloha48 [4]
3 years ago
13

Suppose that you toss a rock upward so that it rises and then falls back to the earth. If the acceleration due to gravity is 9.8

m/sec2,
what is the rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero)?
Assume that air resistance is negligible.

A)The acceleration of the rock is zero.
B)The rock has an upward acceleration of 19.6 m/s2.
C)The rock has a downward acceleration of 19.6 m/s2.
D)The rock has a downward acceleration of 9.8 m/s2.
E)The rock has an upward acceleration of 9.8 m/s2.
Physics
1 answer:
arsen [322]3 years ago
3 0
"The rock has a downward acceleration of 9.8 m/s2" is the one among the following choices that explains the <span>rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero). The correct option among all the options that are given in the question is option "D". </span>
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What is the kinetic energy of a 1.00g hailstone falling at 8.50m/s
bearhunter [10]

Answer:

36.125 J

Explanation:

The formula for kinetic energy is KE = .5(m)(v²).

Using the given information, mass = 1 g and v = 8.50.  Plug that information into the equation.  KE = .5(1)(8.50²) = 36.125 J.

4 0
3 years ago
"Two rooms are connected by a doorway. You are in one room and your friend is in the other room. Explain why you can hear your f
Masteriza [31]

Answer:

You can  hear your friend because of diffraction of sound waves.

Explanation:

Through diffraction of sound waves, the sound waves can bend around the door spaces and spread out through any small opening on the door to reach you in the other room yet the other person is not in a direct line with you.The wavelength of sound waves in this case are longer enough to bend around the obstacle(door and the indirect path) and spread out to reach your room for you to hear your friend without directly being in line with the door for you to see them.

5 0
4 years ago
Read 2 more answers
Complete the sentences below correctly. Stunt Car A and Stunt Car B are identical cars with the same mass of 48.9 kg. They are b
ivann1987 [24]

Answer:

Stunt Car A experiences a large force over a short period of time. Stunt Car B experiences a small force over a long period of time. Because of the force experienced by Stunt Car A, it will sustain more damage than Stunt Car B.

Explanation:

Both cars have the same mass and velocity, therefore they have the same momentum. During the collision, the total momentum of the car A and brick wall is conserved as well as the total momentum of the car B and the pile of leaves.

However, if we are to investigate the damage on each car, we should look at the cars not the whole system. So, the momentum difference between the cars gives us the impulse that the car felt.

\vec{J} = \Delta \vec{P}\\\vec{F}\Delta t = \vec{P}_2 - \vec{P}_1

Since the Car A will crash the wall quicker than the other car crashes through the pile of leaves,

\Delta t_1 < \Delta t_2

which gives us

F_1 > F_2

4 0
3 years ago
A gas storage cylinder in an ordinary chemical laboratory measures wide and high. This is the label on it. Contents: gas Pressur
zhenek [66]

Complete Question

A gas storage cylinder in an ordinary chemical laboratory measures 3.5 cm wide and 9.2 cm high with this label on it:

Contents: N2 Gas

Pressure 18.6 atm

If the cylinder is opened and the gas allowed to escape into a large empty plastic bag, what will be the final volume of nitrogen gas, including what’s collected in the plastic bag and what’s left over in the cylinder?

Use 1 atm for the gas final pressure

Answer:

The final volume is 1647.03cm³ or 1.65 litres

Explanation:

Given

Width of cylinder, W = 3.5 cm

Height of Cylinder, H = 9.2 cm

Gas Initial Pressure, P1 = 18.6 atm

Gas Final Pressure, P2 = 1 atm

First, the initial volume of gas has to be calculated to known the quantity of gas before gas outflow

Volume of Gas, V = Volume of a cylinder

V = πr²h

Given the the width of the cylinder is 3.5cm

This means that the diameter of the cylinder is also 3.5cm

Hence; Diameter, D = 3.5cm

Radius, r = ½D

r = ½ * 3.5cm

r = 1.75cm

So, V1 = πr²h becomes

V1 = π * 1.75² * 9.2

V1 = 28.175π cm³

V1 = 88.55 cm³

From Ideal Gas Law;

PV = nRT

Where k = PV (From Boyle's Law)

P1V1 = P2V2 ---- Make V2 the subject of formula

V2 = (P1V1)/P2

Where P1,P2,V1 and V2 represent the initial pressure, final pressure, initial volume and final volume, respectively.

Recall that P1 = 18.6 atm

P2 = 1 atm

V1 = 88.55 cm³

Final volume, V2 = (P1V1)/P2

V2 = (18.6 atm * 88.55 cm³)/1 atm³

V2 = 1647.03cm³

Convert to Litre

V2 = 1647.03/1000

V2 = 1.64703 litres

V2 = 1.65 L

Hence, the final volume is 1647.03cm³ or 1.65litres

8 0
3 years ago
Been on this question for a while now need help
Katena32 [7]
I think that the answer is D.
6 0
4 years ago
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