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ladessa [460]
3 years ago
9

If we have three different solutions, A, B, and C, each containing 100 g of water, plus respectively 6.84 g of sucrose (C12H22O1

1), 0.72 g of ethanol, and 0.40 g of sodium hydroxide, which statement is true?
a. C has the lowest freezing point in the group.
b. A, B, and C all have different freezing points.
c. A and C have the same boiling point, but B has a lower one.
d. The boiling point of C is lower than that of A or B e. A, B, and C will all have about the same freezing points
Chemistry
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

c. A and C have the same boiling point, but B has a lower one.

Explanation:

The freezing point depression is expressed as:

ΔT = kf×m

Where kf is the freezing point depression constant that depends the nature of the solvent and m is molality (mol of solute/kg of solvent)

Boiling point elevation is:

ΔT = kb×m

Where kb is the ebulloscopic constant of the solvent.

As kf, kb and mass of solvent is the same for A, B and C solutions the only difference will be in moles of solute.

<em>A </em>6,84g of sucrose are:

6,84g×\frac{1mol}{342,3g} = <em>0,002 moles</em>

<em>B </em>0,72g of ethanol are:

0,72g×\frac{1mol}{46,1g} = <em>0,0016 moles</em>

<em>C </em>0,40g of sodium hydroxide are:

0,40g×\frac{1mol}{40g} = <em>0,001 moles</em>

Using Van't Hoff factor that describes the number of moles in solution that comes from 1 mole of solute before dissolving, moles in solution for A, B and C are:

A. moles in solution: 0,02 moles×1 = <em>0,02 moles in solution</em>

B. moles in solution: 0,016 moles×1 = <em>0,016 moles in solution</em>

C. moles in solution: 0,01 moles×2 = <em>0,02 moles in solution</em>

As A has the same moles in solution of C, the freezing point depression will be the same in A and C, and the lower freezing point depression will be in B.

Also, the boiling point will be higher in A and C, and then in B.

Thus:

a. C has the lowest freezing point in the group.  <em>FALSE. </em>A and C have the lowest feezing point because have the higher freezing point depression.

b. A, B, and C all have different freezing points.  <em>FALSE. </em>As moles of A and C are the same, freezing point will be the same for the solutions.

c. A and C have the same boiling point, but B has a lower one.  <em>TRUE. </em>

d. The boiling point of C is lower than that of A or B . <em>FALSE. </em>Boiling point of C and A is higher than B.

e. A, B, and C will all have about the same freezing points. <em>FALSE</em>

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Answer:

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Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}

So, let´s get the number of molecules for each of the options.

a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules

b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules

c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules

d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules

d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules

the smalest number is in option a)

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7 0
2 years ago
What is the pH of a 0.00001 M solution of HCI?
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Answer:

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density of a piece of ebony wood is 1.174 g/ml. what is the volume in quarts of a 2.1549 lb piece of this ebony wood?
lapo4ka [179]

0.88qt

Explanation:

Given parameters:

Density of ebony wood = 1.174g/ml

Mass of wood = 2.1549lb

Unknown:

Volume of the wood in quarts = ?

Solution:

Density is defined as the mass per unit volume of a substance.

Mass is the quantity of matter the wood contains.

Volume is the space it occupies.

To solve this problem, convert the mass form pounds into grams and plug into the density equation to find volume.

Then convert the volume from mL to quarts.

 Density = \frac{mass}{volume}

 Volume = \frac{mass}{density}

    1 pound = 453.592g

   2.1549 lb =  2.1549 x 453.592 = 977.5g

Volume = \frac{977.5}{1.174} = 832.6mL

     1 quart = 946.353mL

        Therefore 832.6mL x \frac{1qt}{946.353} = 0.88qt

learn more:

Density brainly.com/question/8441651

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7 0
3 years ago
please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
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Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

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Unknown:

Limiting reactant = ?

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Using the number of moles, we can ascertain the limiting reactants;

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    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

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