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Elanso [62]
3 years ago
13

A 60.7 kg astronaut is floating in space. She takes her 3.1 kg astronaut drill from her toolbelt and throws it to the right. It

now has a momentum of p to the right and she has a momentum of _____ to the left.
Physics
1 answer:
Sati [7]3 years ago
8 0

Answer:

p to the left

Explanation:

According to law of conservation of momentum "total momentum of an isolated system remains constant".

we consider astronaut and astronaut drill as an isolated system. If the drill gain momentum p to the right so in order for momentum to remain constant the astronaut will gain the same momentum but in opposite direction i.e momentum p to the left.

Initial momentum = 0 ( before she throw astronaut belt)

Final momentum = p - p = 0 (After she throw astronaut belt)

Hence momentum of the system remains constant i.e zero.

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A crate is given a push across a horizontal surface. The crate has a mass m, the push gives it an initial speed of 1.90 m/s, and
Roman55 [17]

Answer:

a) s = 1.534\,m, b) s = 6.135\,m

Explanation:

a) The energy equation for the crate is modelled after the Principle of Energy Conservation and Work-Energy Theorem. Changes in gravitational potential energy can be neglected due to the information of a horizontal surface:

K_{A} = W_{loss}

\frac{1}{2}\cdot m \cdot v^{2} = \mu_{k} \cdot m \cdot g\cdot s

The distance that crate needs to cover before stopping is:

s = \frac{v^{2}}{2\cdot \mu_{k}\cdot g}

s = \frac{(1.90\,\frac{m}{s} )^{2}}{2\cdot (0.120)\cdot (9.807\,\frac{m}{s^{2}} )}

s = 1.534\,m

b) The stopping distance is:

s = \frac{(3.80\,\frac{m}{s} )^{2}}{2\cdot (0.120)\cdot (9.807\,\frac{m}{s^{2}} )}

s = 6.135\,m

3 0
3 years ago
Given a constant acceleration and assuming linear motion, derive equations for velocity and position of a body with respect to t
uysha [10]

Answer:

v = at + u

x = ut+\frac{1}{2}at^{2}+x_{0}

Explanation:

acceleration, a = constant

As we know that acceleration is the rate of change of velocity

a=\frac{dv}{dt}

dv=adt

integrate on both sides

\int dv=\int adt

v = at + u

Where, u is the integrating constant and here it is equal to the initial velocity

Now we know that the rate of change of displacement is called velocity

v = \frac{dx}{dt}

dx=vdt=(u+at) dt

Integrate on both sides

\int dx=\int (u+at) dt

x = ut+\frac{1}{2}at^{2}+x_{0}

where, xo is the integrating constant which is initial position of the particle.

8 0
3 years ago
Which changes do not involve forming or breaking chemical bonds? rusting and cutting burning and melting burning and digesting b
r-ruslan [8.4K]

Answer:

boiling and melting!

Explanation:

These do not make any changes chemically to the substance.

Hope this helps!

6 0
3 years ago
Does the distance a person kicks a soccer ball
3241004551 [841]

Answer:

Independent variable: how far the soccer ball is kicked.

Dependent variable: how well the person does on their math test

Explanation:

The distance the ball is kicked is what the scientist can change. On the other hand, in this experiment, how well the person does on their test supposedly relies on how far the soccer ball is kicked.

5 0
3 years ago
Which of the following statements is NOT true?
Nataly [62]
I think it’s D but i’m not too sure
4 0
3 years ago
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