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3 years ago

Derived eqation motion

Physics

1 answer:

N76 [4]3 years ago

7 0

Answer:

As we have already discussed earlier, motion is the state of change in position of an object over time. It is described in terms of displacement, distance, velocity, acceleration, time and speed. Jogging, driving a car, and even simply taking a walk are all everyday examples of motion. The relations between these quantities are known as the equations of motion.

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3 years ago

After falling from rest at a height of 28.7 m, a 0.502 kg ball rebounds upward, reaching a height of 19.8 m. If the contact betw

Ad libitum [116K]

Answer:

9080 N

Explanation:

Consider the two motions of the ball.

In the downward motion, initial velocity, u, is 0 (because it falls from rest) and the distance is 28.7 m. Using the equation of motion and using g as 9.8 m/s²,

v² = u² + 2as

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For the downward motion, the initial velocity is unknown, the final velocity is 0 and initial velocity is desired. g is negative because the motion is upwars.

0² = v² - 2 × 9.8 × 19.8

v² = 388.08

v = 10.7 m/s

The change in momentum = 0.502(10.7 -(23.7)) = 21.7868 kgm/s

The impulse = change in monetum

Ft = 21.7868 kgm/s

But t = 2.4 ms

$[tex]F = \dfrac{21.7868}{2.4\times10{-3}} = 9078 \text{ N}$ [\tex]

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4 years ago

A series of pulses of amplitude 0.25 m are sent down a string that is attached to a post at one end. The pulses are reflected at

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Answer:

Explanation:

since the string is rigidly attached to the post, the reflected and incident pulses are of the same amplitude but different polarities. At the point where the two pulses meet, the amplitude will be the addition of that of the incident and the reflected pulses. i.e Amplitude= 0.25 + -0.25=0m

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3 years ago

Derived eqation motion​

Derived eqation motion