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Morgarella [4.7K]

3 years ago

14

Derived eqation motion

1 answer:

N76 [4]3 years ago

7 0

Answer:

As we have already discussed earlier, motion is the state of change in position of an object over time. It is described in terms of displacement, distance, velocity, acceleration, time and speed. Jogging, driving a car, and even simply taking a walk are all everyday examples of motion. The relations between these quantities are known as the equations of motion.

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Objects A and B both start at rest. They both accelerate at the same rate. However, object A accelerates for 3x the time as obje

mylen [45]

Answer:

v_Object A = 3v_Object B

OR

1/3v_Object A = v_Object B

Explanation:

Let's see what variables we have in this problem.

Since the objects both start at rest, we have an initial velocity of 0 m/s.

The objects accelerate, so we will have acceleration.

Object A accelerates for 3x the time as Object B, so we have time.

The problem wants us to compare their final speeds, so we have final velocity.

Check what constant acceleration kinematic equation has these variables:

v = v₀ + at

Let's create values for the unknown variables and compare the final velocities.

v = ?
v₀ = 0 m/s (objects start at rest)
a = 5 m/s²
t = 10 s

Since Object A accelerates for 3x the time as Object B, we can use t = 30 s for Object A.

Let's write the two equations:

v = (0) + (5)(10)
v = (0) + (5)(30)

Simplify these equations.

v = 50 m/s
v = 150 m/s

Let's use another set of values to compare the final velocities to see if the velocities differ by 100 m/s or Object A has 3x the final velocity of Object B.

v = ?
v₀ = 0 m/s (objects start at rest)
a = 3 m/s²
t = 7 s

Write the two equations:

v = (0) + (3)(7)
v = (0) + (3)(21)

Simplify these equations.

v = 21 m/s
v = 63 m/s

Now we can clearly see that the final velocities are differed by 3x. Object A has 3x the final speed compared to that of Object B.

3 0

3 years ago

a soccer player kicks a ball with a speed of 30 m/s at an angle of 10. how long does the ball stay in the air?

Brut [27]

3.763 seconds I think

4 0

4 years ago

Read 2 more answers

Derive an expression for the de Broglie wavelength of a thermal neutron and calculate its value at the temperature T = 290 K. Th

Vladimir [108]

Answer:

1.479 A

Explanation:

Expression for de Broglie wave length

λ = $\frac{h}{\left ( 2mKE \right )^{.5}}$

Where m is mass of neutron ,h is plank constant and KE is kinetic energy of

proton.

Kinetic Energy ( KE) = 3 / 2 kT

=1.5 X 1.38 X 10⁻²³ X 290 = 600.3 X 10⁻²³ J

$\sqrt{2mKE}$ = $\sqrt{2\times1.67\times10^{-27}\times600.3\times10^{-23}}$

44.777 x 10⁻²⁵

λ = $\frac{6.626\times10^{-34}}{44.777\times10^{-25}}$

=1.479 A.

7 0

3 years ago

Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak

Mashutka [201]

Answer:

Part a)

$\Delta \phi = 2.2 \pi$

Part b)

$f = 411.3 Hz$

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

$\Delta x = 3\sqrt2 - 3$

$\Delta x = 1.24 m$

now phase difference is related with path difference as

$\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)$

$\Delta \phi = \frac{2\pi}{\lambda}(1.24)$

here in order to find the wavelength

$\lambda = \frac{c}{f}$

$\lambda = \frac{340}{300} = 1.13$

now we have

$\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi$

Part b)

Now we know that when phase difference is odd multiple of $\pi$

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

$\Delta \phi = 3\pi$

so we have

$3\pi = \frac{2\pi}{\lambda}(1.24)$

so we have

$\lambda = 0.827$

now we have

$\frac{340}{f} = 0.827$

$f = 411.3 Hz$

4 0

3 years ago

Which statements are true of all scientific endeavors? Check all that apply.

uranmaximum [27]

A<span>ll scientific endeavors involve experimentation.</span>

5 0

4 years ago