<u>Answer:</u>
<em>Thunderbird is 995.157 meters behind the Mercedes</em>
<u>Explanation:</u>
It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.
Here final velocity 
initial velocity
distance
Distance covered in the slowing down phase = 







The car is in the pit stop for 5s 
After restart it accelerates for 350 m to reach the earlier velocity 71 m/s





total time= 
Distance covered by the Mercedes Benz during this time is given by 
Distance covered by the Thunderbird during this time=
Difference between distance covered by the Mercedes and Thunderbird
= 
Thus the Mercedes is 995.157 m ahead of the Thunderbird.
Answer:
15.7 m
Explanation:
The range (horizontal distance) of the projectile is determined only by its horizontal motion.
The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:

where
v = 12.0 m/s is the initial velocity
is the angle between the direction of v and the horizontal
Substituting,

We know that the projectile hits the ground in a time of
t = 2.08 s
so the horizontal distance covered is

Answer: 10 m/s^2
Explanation:
1) The second law of Newton gives the definition and formula to calculate the net force:
Net force acting on an object = mass * acceleration.
2) From that, when you know the net force acting of the object and its mass, you can solve for the acceleration:
acceleration = Net force / mass
acceleration = 50 N / 5 kg = 10 m/s^2, which is the answer.