Всяко действие има равно по големина и противоположно по посока противодействие.
Answer:
Given, Apparent weight(W₂)=4.2N
Weight of liquid displaced (u)=2.5N
Let weight of body in air = W₁
Solution,
U=W₁-W₂
W₁=4.2=2.5=6.7N
∴Weight of body in air is 6.7N
Answer:
0.19m/s²
Explanation:
Initial velocity(u) = 50×1000/60×60
=13.88 m/s
Final velocity(v) = 36.5×1000/60×60
=10.13 m/s
Acceleration(a) = v-u/t
=10.13-13.88/19.5
a= -0.19m/s²
-a = 0.19m/s²
The magnitude of retar dation is 0.19m/s²
I have no idea what you are trying to ask sorry
<span>The SLOPE of a position-time graph represents an object’s SPEED.
It's not possible to tell the object's velocity from the graph, because
the graph doesn't show anything about what direction the object is
moving, and you need to know the direction in order to know the velocity. </span>