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kati45 [8]
3 years ago
10

What is the affect of applying an unbalanced force on an object?​

Physics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving

Explanation:

hope this helps :)

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The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold 24 x (mass o
matrenka [14]

Answers:

(a) 0.0073kg

(b) Volume gold: 3.79(10)^{-7}m^{3}, Volume cupper: 7.6(10)^{-8}m^{3}

(c) 17633.554kg/m^{3}

Explanation:

<h2>(a) Mass of gold </h2><h2 />

We are told the total mass M of the coin, which is an alloy  of gold and copper is:

M=m_{gold}+m_{copper}=7.988g=0.007988kg   (1)

Where  m_{gold} is the mass of gold and m_{copper} is the mass of copper.

In addition we know it is a 22-karat gold and the relation between the number of karats K and mass is:

K=24\frac{m_{gold}}{M}   (2)

Finding {m_{gold}:

m_{gold}=\frac{22}{24}M   (3)

m_{gold}=\frac{22}{24}(0.007988kg)   (4)

m_{gold}=0.0073kg   (5)  This is the mass of gold in the coin

<h2>(b) Volume of gold and cupper</h2><h2 />

The density \rho of an object is given by:

\rho=\frac{mass}{volume}

If we want to find the volume, this expression changes to: volume=\frac{mass}{\rho}

For gold, its volume V_{gold} will be a relation between its mass m_{gold}  (found in (5)) and its density \rho_{gold}=19.30g/cm^{3}=19300kg/m^{3}:

V_{gold}=\frac{m_{gold}}{\rho_{gold}}   (6)

V_{gold}=\frac{0.0073kg}{19300kg/m^{3}}   (7)

V_{gold}=3.79(10)^{-7}m^{3}   (8)  Volume of gold in the coin

For copper, its volume V_{copper} will be a relation between its mass m_{copper}  and its density \rho_{copper}=8.96g/cm^{3}=8960kg/m^{3}:

V_{copper}=\frac{m_{copper}}{\rho_{copper}}   (9)

The mass of copper can be found by isolating m_{copper} from (1):

M=m_{gold}+m_{copper}  

m_{copper}=M-m_{gold}  (10)

Knowing the mass of gold found in (5):

m_{copper}=0.007988kg-0.0073kg=0.000688kg  (11)

Now we can find the volume of copper:

V_{copper}=\frac{0.000688kg}{8960kg/m^{3}}   (12)

V_{copper}=7.6(10)^{-8}m^{3}   (13)  Volume of copper in the coin

<h2>(c) Density of the sovereign coin</h2><h2 />

Remembering density is a relation between mass and volume, in the case of the coin the density \rho_{coin will be a relation between its total mass M and its total volume V:

\rho_{coin}=\frac{M}{V} (14)

Knowing the total volume of the coin is:

V=V_{gold}+V_{copper}=3.79(10)^{-7}m^{3}+7.6(10)^{-8}m^{3}=4.53(10)^{-7}m^{3} (15)

\rho_{coin}=\frac{0.007988kg}{4.53(10)^{-7}m^{3}} (16)

Finally:

\rho_{coin}=17633.554kg/m^{3}} (17)  This is the total density of the British sovereign coin

6 0
3 years ago
Place the types of radiation in order of INCREASING mass.
lubasha [3.4K]

Answer & explanation:

  • Gamma Radiation (γ):  Also called gamma rays. Gamma radiation is made of electromagnetic waves, has zero charge and mass, continuously emits heat and has the ability to ionize air and make it conductive of electric current.
  • Beta radiation (β): Beta rays or beta particles, are electrons, negative particles with charge - 1 and mass number 0.
  • Alpha radiation (α): Also called alpha particles or alpha rays, are particles charged by two protons and two neutrons.  They have positive charge +2 and mass number 4.
5 0
4 years ago
A car starts from rest and accelerates along a straight line path in one minute it finally attains a velocity of 40 meters/secon
strojnjashka [21]
|Average acceleration| = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning)

                            =        (40 m/s)            -            ( 0 )

                            =   40 m/s .

|Average acceleration| =    (40 m/s)  /  (60 sec)  =  2/3  m/s² .
6 0
3 years ago
State two factors that affect the rate of diffusion of a substance
Ronch [10]

Explanation:

<em>Two</em><em> </em><em>factors</em><em> </em><em>that</em><em> </em><em>affect</em><em> </em><em>the</em><em> </em><em>rater</em><em> </em><em>of</em><em> </em><em>diffusion</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>substance</em><em> </em><em>are</em><em>:</em><em> </em>

  • <em>Diffusion</em><em> </em><em>of</em><em> </em><em>substance</em><em> </em><em>plays</em><em> </em><em>an</em><em> </em><em>important</em><em> </em><em>role</em><em> </em><em>on</em><em> </em><em>cellular</em><em> </em><em>transport</em><em> </em><em>in</em><em> </em><em>plants</em><em>.</em><em> </em>
  • <em>Diffusion</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>passive</em><em> </em><em>movement</em><em> </em><em>of</em><em> </em><em>substance</em><em> </em><em>from</em><em> </em><em>a</em><em> </em><em>region</em><em> </em><em>of</em><em> </em><em>higher</em><em> </em><em>concentration</em><em> </em><em>to</em><em> </em><em>a</em><em> </em><em>region</em><em> </em><em>of</em><em> </em><em>lower</em><em> </em><em>concentration</em><em>. </em>
4 0
3 years ago
The fire department arrive to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away. H
ipn [44]

Answer: The speed is 4 meters per second or 4 m/s.

Explanation:

First, we have the relationship:

Speed = Distance/Time.

In this case, we know that the fire department arrives to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away, this means that:

Time = 210 seconds

Distance traveled in that time = 840m.

Then the speed is:

Speed = 840m/210s = 4 m/s.

The speed is 4 meters per second.

7 0
3 years ago
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