Answer:
What are we supposed to find, if it is kinetic energy then this is the solution.
K.E=1/2mv^2
K.E= kinetic energy
M=mass
V=velocity
K.E =0.5*55*0.6^2
K.E=9.9J
Explanation:
1) the weight of an object at Earth's surface is given by
![F=mg](https://tex.z-dn.net/?f=F%3Dmg)
, where m is the mass of the object and
![g=9.81 m/s^2](https://tex.z-dn.net/?f=g%3D9.81%20m%2Fs%5E2)
is the gravitational acceleration at Earth's surface. The book in this problem has a mass of m=2.2 kg, therefore its weight is
![F=mg=(2.2 kg)(9.81 m/s^2)=21.6 N](https://tex.z-dn.net/?f=F%3Dmg%3D%282.2%20kg%29%289.81%20m%2Fs%5E2%29%3D21.6%20N)
2) On Mars, the value of the gravitational acceleration is different:
![g=3.7 m/s^2](https://tex.z-dn.net/?f=%20g%3D3.7%20m%2Fs%5E2)
. The formula to calculate the weight of the object on Mars is still the same, but we have to use this value of g instead of the one on Earth:
![F=mg=(2.2 kg)(3.7 m/s^2)=8.1 N](https://tex.z-dn.net/?f=F%3Dmg%3D%282.2%20kg%29%283.7%20m%2Fs%5E2%29%3D8.1%20N)
3) The weight of the textbook on Venus is F=19.6 N. We already know its mass (m=2.2 kg), therefore by re-arranging the usual equation F=mg, we can find the value of the gravitational acceleration g on Venus:
![g= \frac{F}{m}= \frac{ 19.6 N}{2.2 kg}=8.9 m/s^2](https://tex.z-dn.net/?f=g%3D%20%5Cfrac%7BF%7D%7Bm%7D%3D%20%5Cfrac%7B%2019.6%20N%7D%7B2.2%20kg%7D%3D8.9%20m%2Fs%5E2)
4) The mass of the pair of running shoes is m=0.5 kg. Their weight is F=11.55 N, therefore we can find the value of the gravitational acceleration g on Jupiter by re-arranging the usual equation F=mg:
![g= \frac{F}{m} = \frac{11.55 N}{0.5 kg} =23.1 m/s^2](https://tex.z-dn.net/?f=g%3D%20%5Cfrac%7BF%7D%7Bm%7D%20%3D%20%5Cfrac%7B11.55%20N%7D%7B0.5%20kg%7D%20%3D23.1%20m%2Fs%5E2)
5) The weight of the pair of shoes of m=0.5 kg on Pluto is F=0.3 N. As in the previous step, we can calculate the strength of the gravity g on Pluto as
![g= \frac{F}{m} = \frac{0.3 N}{0.5 kg} =0.6 m/s^2](https://tex.z-dn.net/?f=g%3D%20%5Cfrac%7BF%7D%7Bm%7D%20%3D%20%5Cfrac%7B0.3%20N%7D%7B0.5%20kg%7D%20%3D0.6%20m%2Fs%5E2)
<span>6) On Earth, the gravity acceleration is </span>
![g=9.81 m/s^2](https://tex.z-dn.net/?f=g%3D9.81%20m%2Fs%5E2)
<span>. The mass of the pair of shoes is m=0.5 kg, therefore their weight on Earth is
</span>
![F=mg=(0.5 kg)(9.81 m/s^2)=4.9 N](https://tex.z-dn.net/?f=F%3Dmg%3D%280.5%20kg%29%289.81%20m%2Fs%5E2%29%3D4.9%20N)
<span>
</span>
Answer:..
1.One light-year = 63,240 AU
2. It’s about 93 million miles (150 million km),or
one astronomical unit (AU) = 92,955,807 miles (149,597,871 km).
The answer to the question is:
75m/s
Just do 25*3