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Anvisha [2.4K]
3 years ago
11

A ball is rolled uphill a distance of 4 meters before it slows, stops, and begins to roll back. The ball rolls downhill 28 meter

s before coming to rest against a tree. What is the magnitude of the ball’s displacement?
Physics
1 answer:
MrRissso [65]3 years ago
4 0
The main assumption is that the ball followed the same way uphill and back, so it was at the same initial point when it rolled back 4 m.

At this moment the displacement was zero (remember that the displacement is the difference between the final position and the initial position).

From that point the ball displaced other 24 m down (28m - 4m = 24 m). And, that is the magnitude of the ball's displacement.

Answer: 24 m.
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Answer:

75 rotations

Explanation:

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(a) use first equation of motion for rotational motion

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(b) Let θ be the angular displacement

use second equation of motion for rotational motion

θ = w0 t + 1/2 α t^2

θ = 0 + 0.5 x 104.67 x 3 x 3

θ = 471.015 rad

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Number of rotation = 471.015 / (2 x 3.14) = 75 rotations

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