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Doss [256]
4 years ago
13

What is the Density of the rock?

Physics
1 answer:
Sindrei [870]4 years ago
4 0
Your answer is gone be 3
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Magnetic fields go from the north poles of magnets to the south poles of magnets.<br> true or false
Novay_Z [31]

The Answer is true, the saying opposites attract are true for magnets when poles match though they repel.

7 0
3 years ago
The balloon's behavior results from a change at the electron level. What do you think might have happened while rubbing the ball
Mariulka [41]

Answer:

Explanation:

opposite charges attract each other, while rubbing the objects together they developed opposite charges which caused them to drift together

6 0
4 years ago
Write a use of magnetic force and frictional force each​
Firdavs [7]
Magnetic force:Computer hard drives use magnetism to store the data on a rotating disk. More complex applications include: televisions, radios, microwave ovens, telephone systems, and computers. ... Frictional force:Quite often uses of friction can be seen from how things would be without friction.
7 0
3 years ago
A racemic mixture can rotate a plane-polarized light in a clockwise direction. Select one: True False
laiz [17]

Answer:

True

Explanation:

8 0
3 years ago
A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for s
Evgen [1.6K]

Answer:

(a) I (Moment of inertia)=0.0987 kgm^{2}

(b) W(Angular Speed)=2.66 \frac{rad}{s}

Explanation:

Given data

m (Monkey mass)= 1.80 kg

d=2.50 m

T (Time Period)=0.940 s

Angle= 0.400 rad

(a) I (Moment of Inertia)=?

(b) W (Angular Speed)=?

For part (a) I (Moment of Inertia)=?

Time Period Formula is given as

T=2(3.14)\sqrt{\frac{I}{mgd} }

After Simplifying we get

I=\frac{mgdT^{2} }{4*(3.14)^{2}}

I=\frac{1.8*9.8*0.25*(0.94)^{2} }{4(3.14)^{2} }

I=0.0987 kgm^{2}

For Part (b) Angular Speed

From Kinetic Energy we get

KE=\frac{1}{2}IW^{2}

Pontential Energy

PE=mgd(1-Cosa)

KE=PE

\frac{1}{2}IW^{2}=mgd(1-Cosa)

W^{2}=\frac{2mgd(1-Cosa)}{I}

W=\sqrt{\frac{2*1.8*9.8*0.25*(1-Cos(0.4)rad)}{0.0987} }

W=2.66\frac{rad}{s}

5 0
3 years ago
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