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3 years ago

Why are there more fat, shaggy bison in Time 3 than in Time 1?

Physics

1 answer:

tatiyna3 years ago

8 0

Answer:

I believe the answer is D.

Explanation:

It would have been helpful if there had been more information included with this problem, but it would make sense that the answer is D. If there is a winter between time 1 and 3, bison that are not well-suited to the weather, (skinny and smooth) will die off, and only the ones well-suited to winter weather will survive to produce offspring.

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Unlike an observational study, an experiment can prove:

Zinaida [17]

A. Cause and effect.

Explanation:

An experiment can prove cause and effect in a study unlike observational studies.

Observational studies is a non-experimental system of investigation.
It helps to identify the causes(independent variable) and the effect(dependent variables).
In observational studies, the variables cannot be controlled and so it is difficult to prove the cause and effect.
An experiment can prove cause and effect because the parameters are tested and can be controlled.

Learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

3 0

3 years ago

A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of

bekas [8.4K]

Answer:

The magnitude of the induced Emf is $0.003371V$

Explanation:

The width of the truck is given as 79inch but we need to convert to meter for consistency, then

The width= 79inch × 0.0254=2.0066 metres.

Now we can calculate the induced Emf using expresion below;

Then the $induced EMF= B L v$

Where B= magnetic field component

L= width

V= velocity

=(40*10^-6) × (42) × (2.0066)

=0.003371V

Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V

8 0

4 years ago

1. Astronomers' ever-expanding knowlage of the universe has coinsided with the development of _____, a collection of indirect di

DerKrebs [107]

The best and most correct answer among the choices provided by your question is the first choice or letter A.

<span> Astronomers' ever-expanding knowledge of the universe has coincided with the development of the cosmic distance scale, a collection of indirect distance measurement.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0

3 years ago

Read 2 more answers

HELP ASAPPP which statement explains the first law of thermodynamics a)energy is created and destroyed or b) energy is transform

Aliun [14]

B I believe... :) good luck!

7 0

4 years ago

Read 2 more answers

Compare the gravitational acceleration on the following objects compared to the Sun using:

arsen [322]

The gravitational acceleration of White dwarf compared to Sun is 13,675.86.

The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

The gravitational acceleration of Star Betelgeuse compared to Sun is 8.5 x 10¹⁰.

<h3>Mass of the planets</h3>

Mass of sun = 2 x 10³⁰ kg

Mass of white dwarf = 2.765 x 10³⁰ kg

Mass of Neutron star = 5.5 x 10¹² kg

Mass of star Betelgeuse = 2.188 x 10³¹ kg

<h3>Radius of the planets</h3>

Radius of sun = 696,340 km

Radius of white dwarf = 7000 km

Radius of Neutron star = 11 km

Radius of star Betelgeuse = 617.1 x 10⁶ km

<h3>Gravitational acceleration of White dwarf compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86$

<h3>Gravitational acceleration of Neutron star compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}$

<h3>Gravitational acceleration of Star Betelgeuse compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}$

Learn more about acceleration due to gravity here: brainly.com/question/88039

3 0

3 years ago