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Daniel [21]
3 years ago
9

Need help on this thermal physics question ASAP please

Physics
1 answer:
Trava [24]3 years ago
6 0
Since V is 5 times larger than C

A) 0V = 25C

25C to 0C = -25
-25 / 5 = -5

so 0C = -5 V

B)

20V x 5 = 100 C


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marshall27 [118]

Answer:

Option-C (Lipoprotein profile)

4 0
2 years ago
A student has a small metal sphere that hangs from an insulating string. The student, in seeking to determine the charge on the
Leokris [45]

Answer:

the answer the correct one is c

Explanation:

Electric charges of different signs attract and those of the same sign repel. In addition, there are two types of insulating bodies, where the loads are fixed (immobile) and metallic (with mobile loads.

Let's analyze the situation presented

* A rod with positive approaches and the sphere is attracted, so the charge on the sphere is negative

* A rod with a negative charge approaches and the sphere is attracted, therefore the charge of the sphere must be positive.

For this to happen, the sphere must be unloaded and the charge that creates the phenomenon are induced charges because the mobile charges of the same sign as the sphere are repelled.

when checking the answer the correct one is c

8 0
3 years ago
High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45
almond37 [142]

Answer:

The speed will be "1.06 m/s".

Explanation:

The given values are:

Momentum,

m1 = 244 g

m2 = 45.2 g

On applying momentum conservation ,

Let v2 become the final golf's speed.  

From Momentum Conservation

⇒  Total \ initial \ momentum = Total \ final \ momentum

⇒  m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2

On putting the estimated values, we get

⇒  0.244\times 57.6+0=0.244\times 39.9+45.2\times v2

⇒  57.844+0=9.7356+45.2\times v2

⇒  48.1084=45.2\times v2

⇒  v2=\frac{48.1084}{45.2}

⇒  v2=1.06 \ m/s

6 0
3 years ago
9. What do you think would happen if your balloon had twice the mass when you launched it? Answer the question using Newton’s Fi
dalvyx [7]
Well that thing doesn’t obey the laws of physics at all. There’s a lot here that you won’t understand kid
8 0
3 years ago
A 39-cm-long vertical spring has one end fixed on the floor. Placing a 2.2 kg physics textbook on the spring compresses it to a
Inessa05 [86]

Answer:

The spring constant is 215.6 N/m.

Explanation:

Given that,

Distance = 39 cm

Compresses length = 29 cm

Mass = 2.2 kg

We need to calculate the distance

Using formula of distance

x=l-l'

Put the value into the formula

x=39-29=10\ cm

We need to calculate the spring constant

Using formula of restoring force

F=kx

k=\dfrac{mg}{x}

Where, F = force

x = distance

Put the value into the formula

k=\dfrac{2.2\times9.8}{10\times10^{-2}}

k=215.6\ N/m

Hence, The spring constant is 215.6 N/m.

7 0
3 years ago
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