Which wave form oscillates both parallel and perpendicular to the direction of the wave motion? transverse waves, longitudinal w
aves, circular waves
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The period of a mechanical wave is 2 seconds. What is the frequency of the wave?
20 waves/second
5 waves/second
2 waves/second
0.5 waves/second
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The object distance for a convex lens is 15.0 cm, and the image distance is 5.0 cm. The height of the object is 9.0 cm. What is the height of the image?
3.0 cm
8.3 cm
27 cm
45 cm
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The period of a mechanical wave is 2 seconds. What is the frequency of the wave?
20 waves/second
5 waves/second
2 waves/second
0.5 waves/second
///////
The object distance for a convex lens is 15.0 cm, and the image distance is 5.0 cm. The height of the object is 9.0 cm. What is the height of the image?
3.0 cm
8.3 cm
27 cm
45 cm
1 answer:
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Answer:
Decreases by times
Explanation:
The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.
The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.
In other words, the sound intensity decreases as inversely proportional to the squared of the distance. i.e.
In the context when the distance was 3 m, the intensity of the sound was =
But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =
= times
Answer:
The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Explanation:
Given that,
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.
The speed of sound in air is 343 m/s.
To find,
The wavelength range for the corresponding frequency.
Solution,
The speed of sound is given by the following relation as :
Wavelength for f = 45 Hz is,
Wavelength for f = 375 Hz is,
So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.