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4vir4ik [10]
3 years ago
8

Which wave form oscillates both parallel and perpendicular to the direction of the wave motion? transverse waves, longitudinal w

aves, circular waves
////////

The period of a mechanical wave is 2 seconds. What is the frequency of the wave?


20 waves/second
5 waves/second
2 waves/second
0.5 waves/second
///////

The object distance for a convex lens is 15.0 cm, and the image distance is 5.0 cm. The height of the object is 9.0 cm. What is the height of the image?


3.0 cm
8.3 cm
27 cm
45 cm

Physics
1 answer:
Solnce55 [7]3 years ago
6 0
Hope this answer helps:)

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An object ends up at a final position of x=-55.25 meters after a displacement of -189.34 meters after a displacement of -189.34
Travka [436]

The initial position of the object was found to be 134.09 m.

<u>Explanation:</u>

As displacement is the measure of difference between the final and initial points. In other words, we can say that displacement can be termed as the change in the position of the object irrespective of the path followed by the object to change the path. So

Displacement = Final position - Initial position.

As the final position is stated as -55.25 meters and the displacement is also stated as -189.34 meters. So the initial position will be

Initial position of the object = Final position-Displacement

Initial position = -55.25 m - (-189.34 m) = -55.25 m + 189.34 m = 134.09 m.

Thus, the initial position for the object having a displacement of -189.34 m is determined as 134.09 m.

4 0
3 years ago
In the following equation , which compounds are the reactants? NaCL+AgNo&gt;NaNo+AgCl
NeX [460]
The first two are always the reactants the products come after so they are last
3 0
3 years ago
Consider an oil droplet of mass m and charge q. We want to determine the charge on the droplet in a Millikan-type experiment. We
Katen [24]

Answer:

q=\frac{mg}{E_o}              

Explanation:

Given:

Charge = <em>q</em>

Electric field strength =E_o

weight of the droplet = <em>mg</em>

The charge is suspended motionless. This is because the electric force on the charge is balanced by the weight of the droplet.

electric force on charged droplet, F=qE_o

This is balanced by the weight, mg

Equating the two:

qE_o=mg\\\Rightarrow q=\frac{mg}{E_o}

4 0
3 years ago
Mandy is testing an unknown solution to determine whether it is an acid or a base. She places a piece of red litmus paper into t
Marina CMI [18]
The solution is a base
5 0
3 years ago
A small boat sailed straight north out of a harbor in strong east wind (blowing from west to east). After sailing for 120 minute
Amiraneli [1.4K]

it can be said that  the speed of the east wind is

v=0.3608m/s

From the question we are told

A small boat sailed <u>straight </u>north out of a harbor in <em>strong </em>east wind (blowing from west to east).

After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km,

  • what is the speed of the east wind?.

<h3> the speed of the east wind</h3>

Generally the equation for the distance  is mathematically given as

BA=3000sin60

BA=2598.07m

Therefore

the speed of the east wind

V_w=\frac{BA}{120*60}\\\\V_w=\frac{2598.07}{120*60}

v=0.3608

For more information on this visit

brainly.com/question/22568180

7 0
2 years ago
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