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Viktor [21]
3 years ago
7

PLEASE HELP ME!!! (20 POINTS im giving it away in a smaller amount because im becoming poor from giving them away)

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

The right side of the equation can be rewritten in terms of p as 4p (4p = 4(x^2 +6) = 4x^2 +24)


Now you have (x^2 +6)^2 - 21 = 4p

Replace (x^2 +6) with p

p^2 - 21 = 4p

Subtract 4p from each side:

p^2 - 21 -4p = 0

Rewrite the expression to get p^2 - 4p -21 = 0


PolarNik [594]3 years ago
6 0

Answer:same!!

Step-by-step explanation:

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Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

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3 0
3 years ago
Please help!!! I'm super confused with this one, show work so that I can figure out what I did wrong.
givi [52]

Answer: The length of CU is 117 units.


Step-by-step explanation:

Given: ΔWCD≈ΔWUV

We know that if two triangles are similar, then their corresponding sides are proportional.

∴ \frac{WU}{WC}=\frac{WV}{WD}

\frac{36x-1}{26}=\frac{110}{20}\\\Rightarrow\ 36x-1=\frac{11}{2}\times26\\\Rightarrow36x-1=143\\\Rightarrow\ 36x=143+1\\\Rightarrow\ 36x=144\\\Rightarrow\ x=4

∴ WU=36(4)-1=143

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crimeas [40]

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