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Marta_Voda [28]
3 years ago
5

A 0.717kg block is attached to a spring with spring constant 19.32N/m. While the block is sitting at rest, a student hits it wit

h a hammer and almost instantaneously gives it a speed of 79.856cm/s. What is the amplitude of the subsequent oscillations in meters?
Physics
1 answer:
hjlf3 years ago
7 0

Answer:

15.38 m.

Explanation:

The kinetic energy of the block is equal to potential energy of spring at maximum compression

1/ 2 m V² = 1 /2 K X²

m is mass of block , V is its velocity , K is spring constant and  X is maximum compression or its amplitude.

X = V\times\sqrt{\frac{m}{K} }

Putting the values

x = 79.856\times\sqrt{\frac{.717}{19.32} }

= 15.38 m.

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Read 2 more answers
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