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lilavasa [31]
3 years ago
9

Newtons second law says that force is equal to

Physics
1 answer:
Aleks04 [339]3 years ago
4 0
For every action there is an opposite and equal reaction. if you think about this u can figure out that force is equal to resistance
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Now, consider whether the following statements are true or false:_____________________________________.
Igoryamba

Answer:

A)F

B)F

C)T

Explanation:

A)

This is not always true that the product of the two vector's always non-negative .It may be positive or negative.

That is why this statement is false.

B)

The unit vectors in three perpendicular direction is i ,j and k.

We know that for unit vectors

i.i=j.j=k.k= 1

i .j= j.k=k.i=0

Therefore only  parallel component of the force will contribute in the integral part instead of perpendicular component of the force.

That is why this statement is false.

C)

This statement is True.

A)F

B)F

C)T

7 0
3 years ago
Planet x has a mass of 4x1022 kg and a radius of 6x105 m What lise the grav ritational field strength in the surface of planet X
SCORPION-xisa [38]

Answer:

  g ≈ 7.4 m/s²

Explanation:

The acceleration due to gravity on planet XX is ...

  g = GM/r² = (6.67·10^-11 × 4·10^22)/(6·10^5)^2

  g ≈ 7.4 m/s²

6 0
3 years ago
In ionic bonding, atoms
Genrish500 [490]
Can i have more information?
3 0
3 years ago
The ratio of translational energy and total energy of a rolling sphere is given by
Rufina [12.5K]
The answer to your question is 5:7
4 0
2 years ago
2200 kg semi truck driving down the highway has lost control. The truck rolls across the median and into oncoming traffic. The t
serious [3.7K]

Answer:

The semi truck travels at an initial speed of 69.545 meters per second downwards.

Explanation:

In this exercise we see a case of an entirely inellastic collision between the semi truck and the car, which can be described by the following equation derived from Principle of Linear Momentum Conservation: (We assume that velocity oriented northwards is positive)

m_{S}\cdot v_{S}+m_{C}\cdot v_{C} = (m_{S}+m_{C})\cdot v (1)

Where:

m_{S}, m_{C} - Masses of the semi truck and the car, measured in kilograms.

v_{S}, v_{C} - Initial velocities of the semi truck and the car, measured in meters per second.

v - Final speed of the system after collision, measured in meters per second.

If we know that m_{S} = 2200\,kg, m_{C} = 2000\,kg, v_{C} = 45\,\frac{m}{s} and v = -15\,\frac{m}{s}, then the initial velocity of the semi truck is:

m_{S}\cdot v_{S} = (m_{S}+m_{C})\cdot v -m_{C}\cdot v_{C}

v_{S} = \frac{(m_{S}+m_{C})\cdot v - m_{C}\cdot v_{C}}{m_{S}}

v_{S} = \left(1+\frac{m_{C}}{m_{S}} \right)\cdot v - \frac{m_{C}}{m_{S}} \cdot v_{C}

v_{S} = v +\frac{m_{C}}{m_{S}}\cdot (v-v_{C})

v_{S} = -15\,\frac{m}{s}+\left(\frac{2000\,kg}{2200\,kg} \right) \cdot \left(-15\,\frac{m}{s}-45\,\frac{m}{s}  \right)

v_{S} = -69.545\,\frac{m}{s}  

The semi truck travels at an initial speed of 69.545 meters per second downwards.

3 0
2 years ago
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