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snow_tiger [21]
3 years ago
8

Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy

Physics
1 answer:
Dominik [7]3 years ago
5 0

a) 0.261 T

b) this field strength is obtainable with today's technology

Explanation:

a)

The force experienced by a charged particle moving perpendicular to a magnetic field is given by

F=qvB

where

q is the charge

v is the velocity

B is the strength of the field

This force is perpendicular to the motion of the particle, which therefore moves in a circular path; and so, this force acts as centripetal force, so we can write:

qvB=m\frac{v^2}{r}

where

m is the mass of the particle

r is the radius of the circle

In this problem, we have:

q=1.6\cdot 10^{-19}C (magnitude of the charge of antiprotons)

v=5.00 \cdot 10^7 m/s (velocity)

m=1.67\cdot 10^{-27}kg (mass of antiprotons)

r = 2.00 m (radius)

Therefore, we can re-arrange the equation and solve to find B, the magnetic field strength:

B=\frac{mv}{qr}=\frac{(1.67\cdot 10^{-27})(5.00\cdot 10^7)}{(1.6\cdot 10^{-19})(2.00)}=0.261 T

B)

The strength of the magnetic field calculated in part A) is

B=0.261 T

This is indeed a very strong magnetic field. In fact, by comparison, the Earth's magnetic field has a strength of about

B_{earth}=5\cdot 10^{-5} T

However, there are current technologies available that are able to produce such strong fields. For instance, the superconducting magnets in the LHC (Large Hadron Collider) are able to produce magnetic fields of strength up to 8 Tesla (8 T).

Therefore, we can say that this field strength is obtainable with today's technology.

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A satellite that weighs 4900 N on the launchpad travels around the earth's equator in a circular orbit with a period of 1.667 h.
charle [14.2K]

Answer:

(a)F= 3.83 * 10^3 N

(b)Altitude=8.20 * 10^5 m

Explanation:

On the launchpad weight = gravitational force between earth and satellite.

W = GMm/R²

where R is the earth radius.

Re-arranging:

WR² / GM = m

m = 4900 * (6.3 * 10^6)² / (6.67 * 10^-11 * 5.97 * 10^24) = 488 kg

The centripetal force (Fc) needed to keep the satellite moving in a circular orbit of radius (r) is:

Fc = mω²r

where ω is the angular velocity in radians/second. The satellite completes 1 revolution, which is 2π radians, in 1.667 hours.

ω = 2π / (1.667 * 60 * 60) = 1.05 * 10^-3 rad/s

When the satellite is in orbit at a distance (r) from the CENTRE of the earth, Fc is provided by the gravitational force  between the earth and the satellite:

Fc = GMm/r²

mω²r = GMm / r²

ω²r = GM / r²

r³ = GM/ω² = (6.67 * 10^-11 * 5.97 * 10^24) / (1.05 * 10^-3)²  

r³ = 3.612 * 10^20

r = 7.12 * 10^6 m

(a) F = GMm/r²  

F=(6.67 * 10^-11 * 5.97 * 10^24 * 488) / (7.12 * 10^6 )²

F= 3.83 * 10^3 N

(b) Altitude = r - R = (7.12 * 10^6) - (6.3 * 10^6) = 8.20 * 10^5 m

4 0
3 years ago
*HELP ASAP* The Earth's___retains the atmosphere from dissipating into space.
stepladder [879]

Answer:

gravity

Explanation:

its correct

8 0
3 years ago
Read 2 more answers
1) Beth rode the Flying Saucer ride at her favorite amusement park. The ride hung from a rod and swung back and forth while simu
quester [9]

#1

Since Beth rode the Flying saucer ride which is spinning on its axis while axis is moving to and fro as well, so here Beth will experience two motions in this case

(i) Spinning motion

(ii) Rotational motion

#2

Jill and Scott both traveled for 30 min

So time of motion for both is 0.5 h as we know that 1 h = 60 min

Now from the formula of speed we know that

speed = \frac{distance}{time}

Speed of Jill

v_1 = \frac{5}{0.5} = 10 km/h

speed of Scott

v_2 = \frac{10}{0.5} = 20 km/h

so correct answer is

B) Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

#3

Since we know that <em>acceleration is rate of change in velocity</em>

So here we can say that every motion where velocity changes with time then it is an accelerated motion.

Now change in velocity occurs when either the magnitude will change or its direction will change because here velocity is a vector quantity and it will change with magnitude and direction both.

so here due to oval path the direction of velocity will changes at many points and hence it will be an accelerated motion.

so correct answer is

<em>C) James was right since the car changed direction during the race.</em>


6 0
3 years ago
Read 2 more answers
if an object is moving with a velocity of 25m/s, an acceleration of 5m/s and has a travel time of 5s, what is the final velocity
miv72 [106K]

V = at + V0

where v0 is the initial speed, a is the acceleration and t is the time.

So:

v = 5m/s^2*5s + 25m/s = 50 m/s

4 0
3 years ago
Why is gasoline so flammable
Karo-lina-s [1.5K]
Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.




Hope this helps




I looked this up




Don't forget to rate and thanks me
8 0
4 years ago
Read 2 more answers
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