<u>Given:</u>
Rate of appearance of O2 = 0.250 M/s
Time period = 5.50 s
<u>To determine:</u>
The concentration of O2 formed
<u>Explanation:</u>
2O3 (g) ↔ 3O2 (g)
Rate of appearance of O2 = 1/3 * Δ[O2]/Δt
Based on the given data:
0.250 M/s = 1/3 * [O2]/5.50 s
[O2 ] = 0.250 Ms⁻¹ * 3 * 5.50 s = 4.125 M
Ans: Amount of oxygen formed is 4.13 M
Answer:
58.6 g.
Explanation:
Hello there!
In this case, since the molecular formula of lithium thiocyanate is LiCNS and therefore its molar mass is 65.1 g/mol, it possible to perform the calculation of the mass of 0.900 moles of this substance by recalling the following equivalence statement:
1 mol = 65.1 g.
Thereby, we can calculate the required mass as shown below:
Best regards!
Answer:
Helium
Explanation:
LOOK AT THE TABLE OF ELEMENTS WOMAN!!!
Answer:
Answer to: Write a balanced half-reaction describing the oxidation of aqueous iodide anions to gaseous diiodine. By signing up, you'll get...
Explanation: