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Luba_88 [7]
3 years ago
11

Pure substances that have properties entirely different from the atoms that make it up are _____.

Chemistry
2 answers:
galina1969 [7]3 years ago
4 0

<span>Pure substances that have properties entirely different from the atoms that make it up are called compounds. All compounds are made up of molecules, but not all the molecules are compounds. Compounds are composed of more than one mixture of atoms. An example of this is Hydrogen Gas, it is a molecule but it is not a compound because it is only made of only one element. But when Hydrogen is mixed with Oxygen, it forms water, which is now a compound because of the mixture of two hydrogen and one oxygen atoms. </span>

hichkok12 [17]3 years ago
3 0

Answer:

compounds

Explanation:

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Two objects are brought into contact Object 1 has mass 0.76 kg, specific heat capacity 0.87) g'c and initial temperature 52.2 'C
taurus [48]

Answer:

T_F=77.4\°C

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

Q_1=-Q_2

In terms of mass, specific heat and temperature change is:

m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)

Now, solve for the final temperature, as follows:

T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}

Then, plug in the masses, specific heat and temperatures to obtain:

T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

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4 0
3 years ago
Gaseous ammonia chemically reacts with oxygen O2 gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of am
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Answer:

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Explanation:

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From the balanced equation above,

4 moles of NH₃ reacted to produce 4 moles of NO.

Finally, we shall determine the number of mole of ammonia, NH₃, needed to produce 1.7 moles of nitrogen monoxide, NO. This can be obtained as follow:

From the balanced equation above,

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