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Artist 52 [7]
2 years ago
9

What is the use of the crystallisation process?

Chemistry
2 answers:
ioda2 years ago
5 0
  •  to obtain pure salt from seawater. 
  • in order to obtain pure crystals of a substance from an impure mixture. 
  • obtain pure alum crystals from an impure alum.

joja [24]2 years ago
4 0

<em><u>to</u></em><em><u> </u></em><em><u>separate</u></em><em><u> </u></em><em><u>pure</u></em><em><u> </u></em><em><u>salt</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>salt</u></em><em><u> </u></em><em><u>water</u></em>

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Which particle in an atom is lost or gained to make an ion
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Write the TOTAL IONIC EQUATION between zinc and hydrochloric acid.
Andreyy89

Answer : The net ionic equation will be,

Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced ionic equation between zinc and hydrochloric acid will be,

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

The ionic equation in separated aqueous solution will be,

Zn(s)+2H^+(aq)+2Cl^-(aq)\rightarrow Zn^{2+}(aq)+2Cl^-(aq)+H_2(g)

In this equation, Cl^- is the spectator ion.

By removing the spectator ion from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)

8 0
3 years ago
A buffer contains significant amounts of ammonia and ammonium chloride.
Oksanka [162]

Answer:

a. HCl + NH₃ ⇄ NH₄Cl

b. KOH + NH₄⁺ ⇄ K⁺ + NH₃ + H₂O

Explanation:

A buffer system is made by a weak base (ammonia, NH₃) and its conjugate acid (ammonium ion NH₄⁺ coming from ammonium chloride NH₄Cl). Its function is to resist abrupt changes in the pH when acids or bases are added.

a. When aqueous hydrochloric acid is added, it reacts with the base of the buffer. The corresponding equation is:

HCl + NH₃ ⇄ NH₄Cl

b. When aqueous potassium hydroxide is added, it reacts with the acid of the buffer. The corresponding equation is:

KOH + NH₄⁺ ⇄ K⁺ + NH₃ + H₂O

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Please someone help I’m really confused
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Answer:10-3

Explanation:

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