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dusya [7]
4 years ago
11

Why is water densest 40 degree Celsius

Chemistry
2 answers:
STALIN [3.7K]4 years ago
7 0
Because of the pressure?
a_sh-v [17]4 years ago
4 0
Because as matter is cooled, the atoms become less active, meaning they dont move. when it heated, they become more active.
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At 25 ∘ C , the equilibrium partial pressures for the reaction 3 A ( g ) + 4 B ( g ) − ⇀ ↽ − 2 C ( g ) + 3 D ( g ) were found to
VMariaS [17]

<u>Answer:</u> The standard Gibbs free energy of the given reaction is 6.84 kJ

<u>Explanation:</u>

For the given chemical equation:

3A(g)+4B(g)\rightleftharpoons 2C(g)+3D(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_C)^2\times (p_D)^3}{(p_A)^3\times (p_B)^4}

We are given:

(p_A)_{eq}=5.70atm\\(p_B)_{eq}=4.00atm\\(p_C)_{eq}=4.22atm\\(p_D)_{eq}=5.52atm

Putting values in above expression, we get:

K_p=\frac{(4.22)^2\times (5.52)^3}{(5.70)^3\times (4.00)^4}\\\\K_p=0.0632

To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314 J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_{eq} = equilibrium constant at 25°C = 0.0632

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (0.0632)\\\\\Delta G^o=6841.7J=6.84kJ

Hence, the standard Gibbs free energy of the given reaction is 6.84 kJ

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4 years ago
When these bond to make ccl4, what is the shape of a ccl4 molecule? linear circular tetrahedral trigonal planar
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Its tetrahedral since there's four chlorine molecules around carbon
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: Please predict products, label the states and write ionic and net ionic equations for each. These are all double replacement r
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4 years ago
Using the synopsis of the article, which of the following is a true statement?
Contact [7]

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3 years ago
What mass of oxalic acid is required to prepare 250 mL of a 2.00 M solution?
melamori03 [73]

Answer:

Hope this helps!

Explanation:

The molarity of a given solution is defined as the total number of moles of solute per litre of solution.

\(Molarity = \frac{n}{V}\)

Here,

M is the molality of the solution

n is the number of moles of the solute

V is the volume of solution given in terms of litres

Molecular weight of oxalic acid (H2C2O4.2H2O) = 126 g/mol.

M = n/V

0.1 M = n/0.25L

n = 0. 025 mol

Number of moles = Given mass/Molar mass

0. 025 mol = m / 126

m = 3.15 g

So, amount of oxalic acid is 3.15 g

6 0
3 years ago
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