Q1) firstly we need to determine the empirical formula of the compound. empirical formula is the simplest ratio of components in the compound. percentages of the elements have been given, so lets assume we are calculating for a compound of 100g C H O mass 63.13 g 8.830 g 28.03 g molar mass 12 g/mol 1 g/mol 16 g/mol number of moles 63.13/12 8.830/1 28.03/16 5.26 8.830 1.75 divide by the smallest number of moles 5.26/1.75 8.830/1.75 1.75/1.75 = 3.01 = 5.04 =1 rounded off to the nearest whole numbers C - 3 H - 5 O - 1 therefore empirical formula = C₃H₅O
Q2) we have to next determine the molecular formula of the compound molecular formula gives the actual composition of elements in the compound. since we know the empirical formula and molecular mass, we can find how many empirical units are in the molecular formula. mass of empirical unit = Cx3 + Hx5 + Ox1 = 12 g/mol x 3 + 1g/mol x 5 + 16 g/mol x 1 = 36 + 5 + 16 = 57 g/mol the molecular mass = 228 g/mol then number of empirical units in the molecular formula = 228 / 57 = 4 therefore there are 4 empirical units then the molecular formula = 4 x empirical formula =4 (C₃H₅O) molecular formula = C₁₂H₂₀O₄
Filtration is useful for separating sediments that are carried in water for easy drinking without the risk of disease - an example of this is a water purifier
