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2 years ago

If you dispense 40 ml of hexane, but it turns out you only need 5 ml, what should you do with the remainder?

Chemistry

1 answer:

Natasha2012 [34]2 years ago

7 0

After subtracting the volume needed from the volume dispensed, we got a remainder of 35ml

<h3>Subtraction of Numbers</h3>

Given Data

Volume of Hexane dispensed = 40ml

Volume needed = 5 ml

Let us compute the amount of excess hexane/ the volume that will remain

Remainder = The difference in volume dispensed and the volume needed

Remainder = 40-5

Remainder = 35 ml

The remainder is 35ml

Learn more about subtraction of numbers here:

brainly.com/question/4721701

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If the hydroxide ion [OH-] concentration of an aqueous solution is 1 x 10 -3 M, what is the [H+] in the solution? Is the solutio

Dominik [7]

Answer:

pH = 11, The solution is Basic.

Explanation:

We know that;

[OH-] [H+] = 1 × 10^-14

we are given; [OH-] as 1 x 10^ -3 M

Therefore, we can get the [H+] by;

[H+] = 1 × 10^-14/[OH-]

= 1 × 10^-14 M/1 x 10^ -3 M

= 1 × 10^-11 M

But; pH = - log [H+]

Thus,

pH = - log (1 ×10^-11 M)

= 11

pH = 11, which means the solution is basic.

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3 years ago

A wooden block has a mass of 125 g and a volume of 55 cm3. What is its density?

leonid [27]

Answer:

d = 2.27 cm3

Explanation:

m = 125 g

V = 55 cm3

m = V × d

=> d = m/V = 125/55 = 2.27 g/cm3

4 0

2 years ago

Apakah maksud inferens

trasher [3.6K]

Answer:

A conclusion based upon reasoning

Explanation: if it is snowing outside, it is reasonable to infer that you need a coat.

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3 years ago

Air at 30.0% relative humidity is cooled isobarically at 1 atm absolute from 75.0°C to 35.0°C. a. Estimate the dew point and the

Dvinal [7]

Answer:

a. Dew point: 48.7°C. Degrees of superheat 26.3°C

b. $3.33mol/m^3$

c. $P=3.34atm$

Explanation:

a. Based on the psychometric chart of air, the specific volume of air at the given conditions is:

$v =\frac{RT}{PM} =\frac{0.082\frac{atm*L}{mol*K}*348.15K}{1atm*28.97g/mol} *\frac{1m^3}{1000L}*\frac{1000g}{1kg} =0.98544m^3/kg$

The dew point at the specific volume and the 30%-humidity has a value of 48.7°C, it means that there are 75°C-48.7°C=26.3°C of superheat.

b. At 75°C the molar fraction of water is 11580Pa/101625Pa=0.114 moles per cubic meter of feed gas are:

$\frac{n}{V}=y_{H_2O}\frac{P}{RT}=0.114\frac{1atm}{0.082\frac{atm*L}{mol*K}*348.15K} }*\frac{1000L}{1m^3} \\\frac{n}{V}=4mol/m^3$

Once the 35°C are reached, the mole fraction of water is 1688Pa/101325Pa=0.017 and remaining moles per cubic meter of feed gas are:

$\frac{n}{V}=y_{H_2O}\frac{P}{RT}=0.017\frac{1atm}{0.082\frac{atm*L}{mol*K}*308.15K} }*\frac{1000L}{1m^3} \\\frac{n}{V}=0.673mol/m^3$

So the condensed moles per cubic meter of feed gas are:

$4mol/m^3-0.673mol/m^3=3.33mol/m^3$

c. Considering the Raoult's law, one computes the pressure as follows:

$P=\frac{P^{sat}_{H_2O}}{y_{H_2O}}$

At 75°C and 30%-humidity, the saturation water vapor pressure has a value of 38599Pa, thus:

$P=\frac{38599Pa}{0.114}*\frac{1atm}{101325Pa} \\P=3.34atm$

Best regards.

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3 years ago

How many grams are there in 1.5x10^25 molecules of CO2?

Arturiano [62]

Answer:

Now, a substance's molar mass tells what the mass of one mole of that substance is. In carbon dioxide's case, its molar mass is equal to 44.01 g/mol , which means that every mole of CO2 will have a mass of 44.01 g

Explanation:

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2 years ago