REACTION TYPE:
Single displacement/Oxidation-reduction
(Hope this helped UwU)
Answer:
a.
9.88
Explanation:
ΔG = - 2.303 RT log Ka
ΔG is change in free energy at temperature T , Ka is equilibrium constant
- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa
- log Ka = 9.88 .
pKa = 9.88 .
8.03 solutions report is described below.
Explanation:
8.03 Solutions Lab Report
In this laboratory activity, you will investigate how temperature, agitation, particle size, and dilution affect the taste of a drink. Fill in each section of this lab report and submit it and your pre-lab answers to your instructor for grading.
Pre-lab Questions:
In this lab, you will make fruit drinks with powdered drink mix. Complete the pre-lab questions to get the values you need for your drink solutions.
Calculate the molar mass of powered fruit drink mix, made from sucrose (C12H22O11).
Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL.
Answer:
The answer is C (or 3 in this case)
Explanation:
I took the test and got it correct and the explanation is that the watershed will flow into more water which spreads that pollution and as it flows could pick up more pollution.
pH. 10 because it is strong base
