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12345 [234]
3 years ago
5

An attack helicopter is equipped with a 20- mm cannon that fires 88.7 g shells in the forward direction with a muzzle speed of 9

29 m/s. the fully loaded helicopter has a mass of 4180 kg. a burst of 89.9 shells is fired in a 4.84 s interval. what is the resulting average force on the helicopter? answer in units of n
Physics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
The impulse imparted to the shells equals the change in the momentum:
Fav*(Delta t)= Delta m*v.
The mass change is
Delta m= n*m= (89.9shells)*(88.7g)=7.97Kg
So the average force is
F=((v)*(Delta m))/t= ((929)*(7.97))/4.84=1529.78 N
Since the velocity of the shells is much greater than the velocity of the helicopter, there is no need to use relative velocity.



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Always pointing away from the wire, this Poynting vector.

<h3>What is the Poynting vector?</h3>

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1 year ago
The near point of a farsighted person's uncorrected eyes is 80 cm. what power contact lens should be used to move the near point
makvit [3.9K]
To solve this problem, we will get f and then we will use it to calculate the power.

So, for this farsighted person,
do = 25 cm and di = -80
Therefore:
1/f = (1/25) + (1/-80) = 0.00275 = 0.275 m

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5 0
3 years ago
Suppose that instead of a long straight wire, a shortstraight wire was used. The distance from the wire to thepoint that the mag
vichka [17]

Answer:

Thus, if field were sampled at same distance, the field due to short wire is greater than field due to long wire.

Explanation:

The magnetic field, B of long straight wire can be obtained by applying ampere's law

B= \frac{\mu_0 I}{2\pi r}

I is here current, and r's the distance from the wire to the field of measurement.

The magnetic field is obviously directly proportional to the current wire. From this expression.

As the resistance of the long cable is proportional to the cable length, the short cable becomes less resilient than the long cable, so going through the short cable (where filled with the same material) is a bigger amount of currents. If the field is measured at the same time, the field is therefore larger than the long wire because of the short wire.

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3 years ago
If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.
Gwar [14]

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Chargeq=2\times10^{-4}C

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

V=\dfrac{E}{Q}

V=\dfrac{6.5}{2\times10^{-4}}

V=32500\ volt

Hence, The electric potential difference is 32500 volt.

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Answer:

The correct statements would be

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It is believed that the oxygen released from early cyanobacteria reacted with dissolved iron ions to form iron oxide.

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