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3 years ago

Flood waters

Chemistry

1 answer:

Nana76 [90]3 years ago

7 0

Answer:

I think the answer is EROSION because it has to do with the movement of sediment.

Explanation:

Hope this helps!

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Which of the following rules is applicable for balancing a chemical equation?

Ber [7]

Answer:

A.) Change only the coefficients

Explanation:

An equation is balanced when there is an equal quantity of each type of element on both sides of a reaction. When balancing an equation, the only way to manipulate the amounts of each element is by changing the coefficient values. The coefficients alter the amount of each molecule in the reaction.

The subscripts cannot be altered. If you were to change the subscripts, you would be altering the amount of atoms in a particular molecule.

7 0

1 year ago

How are the melting points and boiling points of molecular compounds usually different from those of ionic compounds

pentagon [3]

Melting points and boiling points of molecular compound are usually lower than ionic compounds. This is so as only a small amount of energy is required to overcome the weak intermolecular forces of attraction (Van de Waals forces) thus having lower m.p. and b.p.

Ionic compounds require a large amount of energy to overcome the strong electrostatic forces of attraction between the ions, hence having higher mp and bp

6 0

2 years ago

How many moles of copper (Cu) are in 65.8 g Cu?

Veseljchak [2.6K]

<h2>Answer:</h2>

The correct answer is A) 1.04 mol Cu

{65.8 g / 63.55 g/mol}

= 1.04 mol Cu

Explanation:

In 63.55 g of copper metal there are 1 m o l of C u atoms. By dividing the mass of Cu and molar mass, we can easily get the number of moles.

5 0

2 years ago

Read 2 more answers

Which of the following is not a step in the conversion of 1.3 dam3 to L?

Tanya [424]

First put the choices,and the answer is (10^-3L/1mL)^3 is the correct answer.

3 0

2 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

2 years ago