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BartSMP [9]
3 years ago
11

A double slit has a slit separation of 2.02 x 10-6 m, and the first bright fringe of a light is seen at an angle of 16.5º relati

ve to the central maximum. what is this light’s wavelength?
Physics
1 answer:
Scorpion4ik [409]3 years ago
7 0
The answer would be <span>B. 574 nm</span>
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Prior to determining the experimental design, a scientist typically? A. makes observations. B. forms a hypothesis. C. performs a
Umnica [9.8K]

Prior to determining the experimental design, a scientist typically forms a hypothesis. The answer is letter B. this is to prepare the scientist, the possible outcome of their research before the experimental design whether they are wrong or not.

7 0
3 years ago
Covalent Bonds usually bond atoms of which type of elements together?
anzhelika [568]
<h2>Answer: Nonmetals to Nonmetals </h2>

Covalent bonds hold non-metallic atoms together. These atoms have many electrons in their outermost level and have a tendency to gain electrons rather than to yield them.  

In this case the bond is formed by sharing a pair of electrons between the two atoms, one from each atom. Then, this pair of shared electrons is common to the two atoms and holds them together, so that both atoms acquire more stability.

Therefore the correct answer is C.

5 0
4 years ago
Resistance of a conductor is directly proportional to length.<br> a. True<br> b. False
PtichkaEL [24]

If everything else is held constant ... the substance from which
the conductor is formed, its cross-sectional area, its temperature
everywhere along its length ... then yes, its resistance will be
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4 0
4 years ago
A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
4 years ago
I need help finding the answers to number 4
erastova [34]
It is B. if i'm not mistaking 
5 0
4 years ago
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