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Scorpion4ik [409]
3 years ago
12

Perception Distance + Reaction Distance + Braking Distance = _____________.

Physics
1 answer:
scZoUnD [109]3 years ago
4 0

Answer:

option B) is correct

Explanation:

perception distance is the distance traveled by  the vehicle when the driver perceive the hazard situation.

reaction distance  is the distance traveled by the vehicle after seeing the hazard situation and reacting to it.

Braking Distance is the distance traveled by the vehicle after applying the brake.

so, the sum of Perception Distance + Reaction Distance + Braking Distance is called the total stopping distance

hence option B) is correct .

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If the masses of objects increase and their distance from each other remains the same, then the force of gravity between the two
skelet666 [1.2K]

Answer:

the formula for the force of gravity depends  inversely of the distance and directly of the masses.

F_{G} =G\frac{M_{1} M_{2}}{R^{2}}

This means that if the masses increase and their distance remains the same the force will increase proportionally.

4 0
4 years ago
At the lowest point in a vertical dive (radius = 0.58 km), an airplane has a speed of 300 km/h which is not changing. Determine
murzikaleks [220]

Answer:

The centripetal acceleration is a = 11.97 \ m/s^2

Explanation:

From the question we are told that

     The radius  is r =  0.58 \ km =  0.58 * 1000  =  580 \ m

      The speed is v  = 300\ km /hr =  \frac{300 *1000}{1 * 3600 }  =  83.33 \ m/s

The centripetal acceleration of the pilot is mathematically represented as

       a =  \frac{v^2 }{r}

substituting  values

      a =  \frac{(83.33)^2 }{580}

     a = 11.97 \ m/s^2

7 0
3 years ago
Lab: Effects of Human Activity on Freshwater Resources
Katyanochek1 [597]
$(0,,386. Sup apt g 9=6 ‍♂️
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3 years ago
How much power would be needed to lift a 1.0x10^3N crate 1.5m in 5 seconds?
lina2011 [118]

Answer:power =300watts

Explanation:

5 0
3 years ago
Read 2 more answers
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
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