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3 years ago

Perception Distance + Reaction Distance + Braking Distance = _____________.

Physics

1 answer:

scZoUnD [109]3 years ago

4 0

Answer:

option B) is correct

Explanation:

perception distance is the distance traveled by the vehicle when the driver perceive the hazard situation.

reaction distance is the distance traveled by the vehicle after seeing the hazard situation and reacting to it.

Braking Distance is the distance traveled by the vehicle after applying the brake.

so, the sum of Perception Distance + Reaction Distance + Braking Distance is called the total stopping distance

hence option B) is correct .

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A mineral's chemical composition and crystal structure help determine it's ___________.

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Hiya!

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3 years ago

Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 2

Sidana [21]

Answer:

The work done on the wagon is 37 joules.

Explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

$F_n=F-F'$

$F_n=37.2-22.4$

$F_n=14.8\ N$

Work done on the wagon is given by the product of net force and displacement. It is given by :

$W=F_n\times d$

$W=14.8\ N\times 2.5\ m$

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.

7 0

2 years ago

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asambeis [7]

Answer:

The Nucleus

Explanation:

The nucleus contains the majority of an atom's mass because protons and neutrons are much heavier than electrons, whereas electrons occupy almost all of an atom's volume. I hope this helps you :D

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2 years ago

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A vector R is resolved into its components, Rx and Ry. If the ratio of is 2, what is the angle that the resultant makes with the

Artemon [7]

The angle is 26.56 degrees

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2 years ago

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A certain heat engine takes in 300 J of energy from a hot source and then transfers 200 J of that energy to a colder object. Wha

Greeley [361]

Answer:

The efficiency is 0.33, or 33%.

Explanation:

From the thermodynamics equations, we know that the formula for the efficiency of a heat engine is:

$\eta=1-\frac{Q_2}{Q_1}$

Where η is the efficiency of the engine, Q_1 is the heat energy taken from the hot source and Q_2 is the heat energy given to the cold object. So, plugging the given values in the formula, we obtain:

$\eta=1-\frac{200J}{300J}=0.33$

This means that the efficiency of the heat engine is 0.33, or 33% (The efficiency of an engine is dimensionless).

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2 years ago