Question

A dynamite blast blows a heavy rock straight up from the ground with a launch velocity of 160ft/sec. a) Write the height function.

Answer 1

Answer:

y = 160t - 16t²

Explanation:

Using y = ut -1/2gt² where y = height of heavy rock above the ground, u = initial launch velocity of rock = 160 ft/s, g = acceleration due to gravity = 32 ft/s² and t = time.

So, substituting the values of the variables into y, we have

y = (160 ft/s)t -1/2 × 32 ft/s² × t²

y = (160 ft/s)t - (16 ft/s²)t²

y = 160t - 16t²

So, the height function is y = 160t - 16t²