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Mademuasel [1]
3 years ago
9

Are metal ions larger or smaller than the neutral atoms they came from

Chemistry
1 answer:
NeX [460]3 years ago
7 0

Answer: the metal ions or smaller then the neutral

Explanation:

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What is the oxidation number of cl− in the hypochlorite ion clo−?
mariarad [96]

Answer : The oxidation number of chlorine (Cl) is, (+1)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.

The oxidation number of a Group 1 element in a compound is +1.

The oxidation number of a Group 2 element in a compound is +2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is, ClO^-

Let the oxidation state of 'Cl' be, 'x'

x+(-2)=-1\\\\x-2=-1\\\\x=+1

Therefore, the oxidation number of chlorine (Cl) is, (+1)

5 0
3 years ago
ANSWER ASAP PLZ???????????????????????????????????
Furkat [3]

Answer:

The answer should be A

Explanation:

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zhenek [66]

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b

Explanation:

kloroplast

8 0
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If normal rainwater has a pH of about 6.50, what is the hydrogen ion concentration, [H+]?
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.000000316

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13.00 g of hydrazine reacts with
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Hydrazine is a mixed chemical...look up what is in Hydrazine. Then find the chemicals in it. 13.00g of hydrazine can react to anything....water, gas, etc. but it might not be visible.
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