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VLD [36.1K]
4 years ago
6

An atom has 29 protons, 29 electrons, and 35 neutrons. What is the mass number of the atom?

Physics
2 answers:
BartSMP [9]4 years ago
8 0
The mass number is 64
Ilya [14]4 years ago
5 0
The mass number will be 64 as to calculate the mass you add up the protons and neutrons.

Hope this helps!
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. You have completed your design of a new surgical headlamp. You have decided to power the headlamp using four AA rechargeable b
SSSSS [86.1K]

Answer:

LED run before the batteries are depleted is 3.87 hours

Explanation:

given data

battery = 4 AA

battery is rated = 1.2V, 2550 mAh

power = 3 W

efficient = 95%

to find out

How long will the LED run before the batteries are depleted

solution

we consider here power delivered by battery is = x

so power = x × efficient

3 = x 95%

x = 3.15 W

and

voltage by 4 battery is = 4 × 1.2 = 4.8 V

so current will be = \frac{x}{volatge}

current = \frac{3.15}{4.8}

current = 0.6577 A

so total discharge hours = \frac{2550}{current}

total discharge hours = \frac{2550}{657.7}

time = 3.87 hours

so LED run before the batteries are depleted is 3.87 hours

5 0
3 years ago
You are driving your car, and the traffic light ahead turns red. you apply the brakes for 2.26 s, and the velocity of the car de
Lorico [155]

Let the initial velocity of the car be u.

Final velocity of the car (v) = 5.43 m/s

deceleration (a) = - 2.78 m/s^2

Time taken (t) = 2.26 s

Using the first equation of motion:

v = u + at

u = v - at

u = 5.43 - (-2.78 \times 2.26)

u = 5.43 + 6.28

u = 11.71 m/s

Let the car's displacement be x.

Using second equation of motion:

x = ut + \frac{1}{2}at^2

x = 11.71 \times 2.26 - \frac{1}{2} \times 2.78 \times 2.26^2

x = 26.4646 - 7.0995

x = 19.3651 meters

Hence, the displacement of the car is 19.36 meters

6 0
3 years ago
Performs Parts 1-3 in lab, Part 4 you answer by using your information gathered through Parts 1-3.
elena55 [62]
Oh okie oh gosh lol lol
5 0
3 years ago
The work function of a metal surface is 4.80 × 10-19 J. The maximum speed of the electrons emitted from the surface is vA = 7.7
poizon [28]

Answer:

\lambda_A=2.65177\times 10^{-7}\ m

\lambda_B=3.32344\times 10^{-7}\ m

Explanation:

h = Planck's constant = 6.63\times 10^{-34}\ m^2kg/s

c = Speed of light = 3\times 10^8\ m/s

m = Mass of electron = 9.11\times 10^{-31}\ kg

W_0 = Work function = 4.8\times 10^{-19}\ J

v_A = Velocity of A particle = 7.7\times 10^5\ m/s

v_B = Velocity of B particle = 5.1\times 10^5\ m/s

The wavelength is given by

\lambda=\frac{hc}{\frac{1}{2}mv^2+W_0}

\lambda_A=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(7.7\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_A=2.65177\times 10^{-7}\ m

The wavelength \lambda_A=2.65177\times 10^{-7}\ m

\lambda_B=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(5.1\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_B=3.32344\times 10^{-7}\ m

The wavelength \lambda_B=3.32344\times 10^{-7}\ m

5 0
4 years ago
Find the steady-state temperature distribution for the semi-infinite plate problem
jeka94

Answer:

Savage is the answer

Explanation:  The savage people guess like me

6 0
3 years ago
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