Answer:
3 cm³
Explanation:
Density of the cork = 0.6 g/cm³
Density of water = 1 g/cm³
Volume of cork = 5 cm³
We all know that the formula for density is given as
Density = mass/volume,
The mass of the cork is
Mass = density * volume
Mass = 0.6 * 5
Mass = 3 gram
Given that the density is 0.6, and it is partially floating, then we can say that the volume of the cork below the water is
5 * 0.6 = 3 cm³
Answer:
first option
Explanation:
we know the total amount of charges should be constant so
3 + (-3) + 5 + (-3) = 2
1 + 1 = 2 true
6 + 8 = 14 false
2 + (-2) = 0 false
5 + 3 = 8 false
Answer:
it shows that co2 is absorbed by the atmosphere.
when the animals respire they produce co2 which is release in atmosphere and in presence of sunlight and chlorophyll the plants manufacturs the food and releases the oxygen in the atmosphere .
<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>
Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m).
The point then lies on the y-axes at d = 0.03 m.
from symmetry, the field at that point will be ascending along the y-axes.
A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point.
Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength.
All in all, the infinitesimal field strength from the charge between x and x+dx is:
dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2)
Therefore, upon integration,
E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2.
This gives:
E = k lambda L / (d sqrt((L/2)^2 + d^2) )
But lambda L = Q, the total charge on the rod, so
E = k Q / ( d * sqrt((L/2)^2 + d^2) )
