Answer:
(a)Velocity of wind = 35 j
(b)Velocity of jet relative to air = 425 i
(c)True velocity of jet = 425 i + 35 j
(d)True speed of jet = = 426.88 mi/h
Direction of jet is, ∅ = = 5.38°
Explanation:
We can represent east direction by i and north direction by j.
The jet has a relative speed of 425 mi/h relative to the air.
The wind is blowing due north with a speed of 35 mi/h = 35 j
425 mi/h is the relative speed with respect to wind that is
Velocity of jet wrt wind= =
425 i = - 35 j
= 425 i + 35 j
(a)Velocity of wind = 35 j
(b)Velocity of jet relative to air = 425 i
(c)True velocity of jet = 425 i + 35 j
(d)True speed of jet = = 426.88 mi/h
Direction of jet is,
∅ = = 5.38°
Answer:
a)
b)
Explanation:
Part a
For this case we can begin finding the period like this:
Then we know that the centripetal acceleration is given by:
And the velocity is given by:
If we replace this into the acceleration we got:
And we can replace the values and we got:
Part b
For this case we want to find a value of k such that:
Where a = 9.74, so then we can solve for k like this:
Answer:
162500000.
Explanation:
Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as
I=Current
q=Charge
t=time
q= I t
q= 260 m t
The total number of electron = n
q= n e
n=162500000 t
The number of electron passe per second will be 162500000.