<u>Answer:</u> The volume of NaOH required to reach the endpoint is 100 mL
<u>Explanation:</u>
To calculate the volume of NaOH, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the volume of NaOH required to reach the endpoint is 100 mL
Skeleton equation is actually a chemical reaction whee the reactants and products are written in their chemical formula. In this problem, this is actually a combustion reaction of butane. The chemical formula for butane is C₄H₁₀.
<em>C₄H₁₀ (l) + 6.5 O₂ (g) --> 4 CO₂ (g) + 5 H₂O (l)</em>
Answer: The students should take 49.67 g acid acetic in benzene solution. With significant digits 4.967X10 g.
Explanation: If 220 g solution 30.2% w/w acetic acid has 66.44 g acid acetic (220 g solution * 30.2%), 49.67 g solution 30.2% acetic acid has 15 g acetic acid (with a simple three rule, 15 g acetic acid*220 g solution/66.44 g acetic acid)
Answer:
13.20 litres
Explanation:
use pascal's law of volume and temperature