2 years ago

Why is it important to write a lab report once the experiment is finished?

1 answer:

5 0

Answer:

Anyone should be able to read the lab report, repeat the experiment, and get the same results. This is important for scientists. ... They help the scientists know what has been done before and how it was performed. This can help them design experiments for their own research

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Sodium (Na) has 11 protons and 12 neutrons. What is its isotope notation?

DedPeter [7]

Answer:

Na ²³

ndnxnxnxnxnxnxnxnxn

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3 years ago

Explain why there is a difference in the thickness of the crust between the side of the moon facing the Earth and the side that

Ray Of Light [21]

Answer:

the lack of maria; the thicker crust means it was harder for giant impacts to pierce the crust and get darker basaltic lava bubbling up.

Explanation:

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2 years ago

2. What will you change (the independent variable) in each test?

skad [1K]

Answer:the other vaiabable

Explanation:

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3 years ago

Which of the following sets of oxidation numbers is NOT correct? KMnO4 : K +2, Mn +6, O -2 NaCHO2 : Na +1, C +2, H +1, O -2 Zn(O

muminat

KMnO4 has the incorrect set of oxidation numbers. Whenever there is an alkali metal, it has an oxidation number of +1. As you can see, K is said to have an oxidation number of +2, so it is incorrect.

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2 years ago

The position of the equilibrium for a system where K = 6.4 × 10 9 can be described as being favoring ________________

geniusboy [140]

Answer:

to the right (products side)

Explanation:

The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:

a A + b B → c C + d D

The equilibrium constant expression is:

$K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }$

A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).

Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.

Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.

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2 years ago