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djverab [1.8K]
2 years ago
15

An airplane traveling at 201 m/s makes a turn. What is the smallest radius of the circular path (in km) that the pilot can make

and keep the centripetal acceleration under 5.0 m/s2 ?
Physics
1 answer:
egoroff_w [7]2 years ago
4 0

Answer:

the smallest radius of the circular path is 8.1 km

Explanation:

The computation of the smallest radius of the circular path is given below:

Given that

V = Velocity = 201 m/s

a_c = acceleration = 5 m/s^2

radius = ?

As we know that

a_c = V^2 ÷ r

5 = 201^2 ÷ r

r = 201^2 ÷ 5

= 8,080.2 g

= 8.1 km

Hence, the smallest radius of the circular path is 8.1 km

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poizon [28]

Answer:

4.048\times 10^{-7}\ m

Explanation:

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

c = Speed of light = 3\times 10^8\ m/s

E = Energy = 4.91\times 10^{-19}\ J

Wavelength ejected is given by

\lambda=\dfrac{hc}{E}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{4.91\times 10^{-19}}\\\Rightarrow \lambda=4.048\times 10^{-7}\ m

The maximum wavelength in angstroms of the radiation that will eject electrons from the metal is 4.048\times 10^{-7}\ m

4 0
3 years ago
1. A piece of metal weighs 50.0 N in air, 36.0 N in water, and 41.0 N in an unknown
denis23 [38]

Answer:

a) 3.37 x 10^{3} kg/m^3

b) 6.42kg/m^{3}

Explanation:

a) Firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .

Weight of metal in air = 50N = mg implies the mass of metal is 5kg.

Now the difference of weight of the metal in air and water = upthrust acting on it = volume (metal) p (liquid) g = V (1000)(10) = 14N. So volume of metal piece = 14 x 10^{-4}  kg/m^{3}. So density of metal = mass of metal / volume of metal = 5 / 14 x 10^{-4}  kg/m^{3} = 3.37 x 10^{3} kg/m^3

b) Water exerts a buoyant force to the metal which is 50−36 = 14N, which equals the weight of water displaced. The mass of water displaced is 14/10 = 1.4kg Since the density of water is 1kg/L, the volume displaced is 1.4L. Hence, we end up with 3.57kg/l. Moreover, the unknown liquid exerts a buoyant force of 9N. So the density of this liquid is 6.42kg/m^{3}

3 0
3 years ago
Based on the data you found, about how many of the 100 aliens would become thin if the temperature were 35 C?
saw5 [17]

Answer:

Option D: More than 90

Explanation:

Thickness probably depends on temperature. The higher the temperature, the more aliens we expect to be thin.

5 0
3 years ago
Read 2 more answers
When heat moves from the ocean to the surrounding air, which is this an example of?
Blizzard [7]
B) The transfer of energy from the hydrosphere to the atmosphere

This is because oceans are part of the hydrosphere. As the air warms it flows up into the atmosphere.

Hope this helps!
6 0
2 years ago
A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches
Alexeev081 [22]

Answer:26.83secs

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U=0

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3600=5t^2

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720=t^2

t=√720

t=26.83secs

5 0
3 years ago
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