M= 130 kg
v= 5 m/s
kinetik energy = ½• m•v²
= ½ • 130• 5²
= ½•130•25
= ½•3250
= 1625.
Momentum is described as the result of the calculation of mass multiplied by that thing's velocity.
<span>
In equational formula we can write it: </span>
<span>
P (momentum) = m(mass) * v(velocity) </span>
so to find the mass, revert the equation:
<span>
P = m v </span>
m = P / v
now for the value entry,
<span>
m = 2.5 * 10^4 kgm/s / 30 m/s </span>
<span>
m = 8,3 * 10^2 kilograms
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Answer:
mass multiplied by velocity (4 words but uh
Answer:
39.40 MeV
Explanation:
<u>Determine the minimum possible Kinetic energy </u>
width of region = 5 fm
From Heisenberg's uncertainty relation below
ΔxΔp ≥ h/2 , where : 2Δx = 5fm , Δpc = hc/2Δx = 39.4 MeV
when we apply this values using the relativistic energy-momentum relation
E^2 = ( mc^2)^2 + ( pc )^2 = 39.4 MeV ( right answer ) because the energy grows quadratically in nonrelativistic approximation,
Also in a nuclear confinement ( E, P >> mc )
while The large value will portray a Non-relativistic limit as calculated below
K = h^2 / 2ma^2 = 1.52 GeV
The answer is C, a peer group.
