Question

A truck’s suspension spring each have a spring constant of 769 N/m. If the potential energy of the right front spring is 250 J, how far is the spring compressed?

Answer 1

Answer:

x = 0.81 m

Explanation:

given,

spring constant, k = 769 N/m

Potential energy of the spring = 250 J

distance of spring compression = ?

using conservation of energy

potential energy will equal to the spring energy

$PE = \dfrac{1}{2}kx^2$

$250= \dfrac{1}{2}\times 769\times x^2$

   x² = 0.650

  x = 0.81 m

Hence, the spring is compressed to  0.81 m