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Musya8 [376]
3 years ago
9

What is the potential energy of the products minus potential energy of the reactants?

Chemistry
1 answer:
Arlecino [84]3 years ago
7 0
<span>Exothermic reactions have a potential energy difference between the products and reactants that is negative. </span>
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your friend offers to show you an intrusive igneous rock. which of the following would you expect to see?
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Read 2 more answers
The heat capacity of air is much smaller than that of water, and relatively modest amounts of heat are needed to change its temp
LekaFEV [45]

Answer:

Q=9.2x10^5J

t=614s=10.2min

Explanation:

Hello,

In this case, we can compute the energy by using the following formula for air:

Q=nCp\Delta T

Whereas the moles of air are computed via the ideal gas equation at room temperature inside the 5.5m x 6.5m x 3.0m-room:

n=\frac{PV}{RT}\\\\V=5.5m*6.5m*3.0m=107.25m^3*\frac{1000L}{1m^3}=107250L\\ \\n=\frac{1atm*107250L}{0.082\frac{atm*L}{mol*K}*298.15K}\\ \\n=4386.8mol

Now, we are able to compute heat, by considering that the temperature raise is given in degree Celsius or Kelvins as well:

Q=4386.8mol*21\frac{K}{mol*K}*10K \\\\Q=9.2x10^5J

Finally, we compute the time required for the heating by considering the heating rate and the required heat, shown below:

t=\frac{9.2x10^5J}{1.5\frac{kJ}{s}*\frac{1000J}{1kJ} } \\\\t=614s=10.2min

Regards.

8 0
3 years ago
Will these changes increase, decrease, or have no effect on the mean free path of the molecules in a gas sample?
lisabon 2012 [21]
According to the kinetic theory, the mean free path is the average distance a single atom or molecule of an element or compound travels with respect with the other atoms during a collision. The greater the mean free path, the more ideal the behavior of a gas molecule is because intermolecular forces are minimum. To understand which factors affect the mean free path, the equation is written below.

l = μ/P * √(πkT/2m), where
l is the mean free path
μ is the viscosity of the fluid
P is the pressure
k is the Boltzmann's constant
T is the absolute temperature
m is the molar mass

So, here are the general effects of the factors on the mean free path:

Mean free path increases when:
1. The fluid is viscous (↑μ)
2. At low pressures (↓P)
3. At high temperatures (↑T)
4. Very light masses (↓m)

The opposite is also true for when the mean free path decreases. Factors that are not found here have little or no effect.
6 0
4 years ago
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