a. Force is 2. 30 * 10^-18 Newton
b. Acceleration is 3. 43 * 10^8 m/s²
c. The speed of the particle when it reaches the bottom plate is 2,869. 14 m/s
The vertical displacement is 6 × 10^-3m
<h3>Part 1:</h3>
To determine the force on the particle, use the formula;
Force = Electric field × charge
Note that electric field = E= V * d
Where V = potential difference = 600V
d = distance between plates = 12* 10^-3 m
Charge = 3.2 * 10^-19 C
Substitute values into the formula
Force= 600 * 12* 10^-3 * 3.2 * 10^-19
Force = 2. 30 * 10^-18 Newton
b. To find the acceleration, use the formula
Acceleration = Force/ mass
mass = 6.7 * 10^-27 kg
Force = 2. 30 * 10^-18 N
Substitute the values into the formula
Acceleration =
Acceleration = 3. 43 * 10^8 m/s²
c. To calculate the speed, use the formula
v² = u + 2as
Bute note that at rest, u = 0
v² = 0+ 2as
v =
v =
v =
v = 2,869. 14 m/s
<h3>
</h3>
<h3>
Part 2: How to determine the vertical displacement</h3>
Using the formula:
y = 0.5 Q E L L / (m v v)
Where
y = vertical displacement
Q = charge in the electric field
E = electric field strength
v = horizontal velocity
L = length of the plates
y =
y =
y =
y = m
Thus, the vertical displacement is 6 × 10^-3m
Learn more about vertical displacement here:
brainly.com/question/20845397
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