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Tanya [424]
3 years ago
10

CALCULATE: Ken is a bicyclist. He is moving from point C to point D up a hill. His starting velocity is 8m/s east and 1 second l

ater, his final velocity is at 7m/s east. What is his average acceleration? HINT: use the acceleration formula. A. 1 m/s^2. B. 7.5 m/s^2east. C. -1m/s^2 east. D. 10 m/s^2east.
Physics
1 answer:
tatiyna3 years ago
5 0

Answer:

C. -1m/s² east

Explanation:

starting velocity u= 8m/s

final velocity  v=7m/s

time t=1second

we know,

average acceleration=(v-u)/t

                                   ={ (7-8)/1 } m/s²

                                   =(-1/1 ) m/s²

                                    =-1 m/s²

the result is negative because his  final velocity is less than  starting velocity. That means there will be deceleration instead of acceleration.

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The complete question is as follows:

An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is  1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?

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