<span>Separate this redox reaction into its component half-reactions.
Cl2 + 2Na ----> 2NaCl
reduction: Cl2 + 2 e- ----> 2Cl-1
oxidation: 2Na ----> 2Na+ & 2 e-
2) Write a balanced overall reaction from these unbalanced half-reactions:
oxidation: Sn ----> Sn^2+ & 2 e-
reduction: 2Ag^+ & 2e- ----> 2Ag
giving us
2Ag^+ & Sn ----> Sn^2+ & 2Ag </span>Steve O <span>· 5 years ago </span><span>
</span>
Is a potential to provide effective treatment with fewer side effects than a traditional therapy.
Answer:
In this process The more dense gases are collected in a gas jar. Carbon dioxide, Nitrogen dioxide are collected by this way. Air is displaced upward thus, this process is known as upward delivery
Hope it helped :)
Dude, writing someone else’s story or essay isn’t allowed, so i’ll just give some pointers
so the dude on the throne, a monarch, most likely the king, has a diamond or some other precious object in his hand. meanwhile, there’s a dude sitting on the floor, he looks unhappy, distressed, and maybe a little surprised. so what do you think happened to get to this point? what or who gave the king the diamond? why is the dude on the floor upset? then what’s going to happen? what’s the upset dude gonna
do? what’s the king gonna do? think of answers to the questions and it should start to form
Explanation:
Relation between entropy change and specific heat is as follows.
The given data is as follows.
mass = 500 g, 
= 24.4 J/mol K
= 500 K, 
= 250 K
Mass number of copper = 63.54 g /mol
Number of moles = 
= 
= 7.86 moles
Now, equating the entropy change for both the substances as follows.
![7.86 \times 24.4 \times [T_{f} - 250]](https://tex.z-dn.net/?f=7.86%20%5Ctimes%2024.4%20%5Ctimes%20%5BT_%7Bf%7D%20-%20250%5D)
= ![7.86 \times 24.4 \times [500 -T_{f}]](https://tex.z-dn.net/?f=7.86%20%5Ctimes%2024.4%20%5Ctimes%20%5B500%20-T_%7Bf%7D%5D)
= 750
So, 
= 
- For the metal block A, change in entropy is as follows.
= ![24.4 log [\frac{375}{500}]](https://tex.z-dn.net/?f=24.4%20log%20%5B%5Cfrac%7B375%7D%7B500%7D%5D)
= -3.04 J/ K mol
- For the block B, change in entropy is as follows.
= ![24.4 log [\frac{375}{250}]](https://tex.z-dn.net/?f=24.4%20log%20%5B%5Cfrac%7B375%7D%7B250%7D%5D)
= 4.296 J/Kmol
And, total entropy change will be as follows.
= 4.296 + (-3.04)
= 1.256 J/Kmol
Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol and change in entropy of block B is 4.296 J/Kmol.
