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jeyben [28]
3 years ago
14

How you could use a microscope to determine if a simple was either a prokaryote or a eukaryote

Chemistry
2 answers:
Black_prince [1.1K]3 years ago
3 0
You could check if their cells had a nucleus or not. If it did it would be a eukaryote, if it did not then it would be a prokaryote.
qwelly [4]3 years ago
3 0

Defined as pre-nucleus, prokaryotes are cells that contain no membrane-based organelles, including a nucleus.

Mostly recognized as bacteria, two prokaryotic kingdoms exist: Monera or Bacteria and Archaea.

Seemingly simple in structure and markedly different from eukaryotic and protist organisms, many scientists believe prokaryotic cells were amongst the first on the Earth and very well may out-survive all other organisms.

http://www.microscopemaster.com/prokaryotes.html

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If I have 450 grams of iorn how many miles of it do I have
Alja [10]

Answer:

sorry this is a kind of confusing question.

Explanation:

4 0
3 years ago
9) Give the set of four quantum numbers that could represent the extra electron added (using the Aufbau principle) to the neutra
Pie

Answer:

See explanation

Explanation:

9) If an extra electron is added to the neon atom, then the electronic configuration becomes; 1s2 2s2 2p6 3s1

This last electron has quantum numbers;

n=3, l=0, m=0 and s = +1/2

This is so because the 2s level is already filled so the extra electron must go into the 3s level. The orbital quantum number and the magnetic quantum number for the s orbital is zero.

10) Electron affinity is the energy released when one mole of gaseous atoms accept one mole of gaseous electrons to form one mole of gaseous ions having a negative charge.

In the second period, fluorine has the greatest electron affinity since electron affinity increases across the period. The noble gas, neon has an electron affinity of 0KJ/mol.

11) Ionization energy decreases down the group but increases across the period due to increase in the size of the nuclear charge and decrease in the distance between the nucleus and the outermost electron. Hence, the process; Br+(g) ---->Br2+(g) + e- has the greatest ionization energy. Recall that the second ionization is always higher than the first ionization energy.

12)The order of decreasing metallic character here is K> As> P. Even though As and P belong to the same group, we must note that metallic character increases down the group hence the order written above.

3 0
2 years ago
Draw the structure of the fat or oil that would result when a glycerol molecule is
charle [14.2K]

Glycerol will react with 3 butanoic acid molecule to produce glyceryl tributyrate.

Explanation:

You may find the chemical reaction and the structure of molecules in the attached picture.

Learn more about:

triglyceride

brainly.com/question/875089

brainly.com/question/11595668

#learnwithBrainly

3 0
3 years ago
Ca+HCI—>CaCI2+H2, what is the reaction?
arsen [322]

Answer:

single replacement reaction

Explanation:

This is a kind of single replacement reaction where you switch either cations or anions. Here you switched Ca for H and produced Cacl2 and H2 gas by itself.

4 0
3 years ago
Read 2 more answers
A pure copper penny contains approximately 2.9×1022 copper atoms. Use the following definitions to determine how many ______ of
hammer [34]

Complete question is;

A pure copper penny contains approximately 2.9 × 10^(22) copper atoms.

1 doz = 12

1 gross = 144

1 ream = 500

1 mol = 6.022 × 10^(23)

Use these definitions to determine the following:

A) How many dozens of copper atoms are in a penny.

B) How many gross of copper atoms are in a penny

C) How many reams of copper atoms are in a penny.

D) how many moles of copper atoms are in a penny?

All answers can be rounded to two significant figures

Answer:

A) 2.4 × 10^(21) dozens

B) 2.01 × 10^(20) gross

C) 5.8 × 10^(19) reams

D) 0.048 mol

Explanation:

A) A dozen contains 12.

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/12 dozens = 2.42 × 10^(21).

In 2 significant figures, we have;

2.4 × 10^(21) dozens

B) 1 gross = 144

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/144 gross ≈ 2.01 × 10^(20) gross

C) 1 ream = 500

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/500 reams = 5.8 × 10^(19) reams

D) 1 mol = 6.022 × 10^(23)

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/(6.022 × 10^(23)) = 0.048 mol

6 0
3 years ago
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