Answer:
When light is shone on to the surface of a metal, its electrons absorb small amounts of energy and become excited into one of its many empty orbitals. The electrons immediately fall back down to lower energy levels and emit light. This process is responsible for the high luster of metals.
Explanation:
<em> </em><em>Your </em><em>well-wisher</em><em> </em><em>:-)</em>
Reactant + reactant = product
C + O2 = CO2
carbon dioxide is what's being made is product
the reagents necessary to convert alcohol to ketone
which involves oxidation of alcohols.
<h3>
What is oxidation of alcohols?</h3>
- Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
- In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
- In order to cause primary alcohols to oxidize into aldehydes
(dichromate)
/pyridine (Collins reagent)- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern
- oxidation of secondary alcohols to ketones
(dichromate)
/pyridine (Collins reagent)- Chromium pyridinium compound (PCC)
- Dichromate of pyridinium (PDC, Cornforth reagent)
- Periodinane by Dess-Martin
- Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
/acetone (Jones oxidation)- Acetone with aluminum isopropoxide (Oppenauer oxidation)
To learn more about oxidation of alcohols with the given link
brainly.com/question/7207863
#SPJ4
<u>Question:</u>
Identify the reagents necessary to achieve each of the following transformations




Answer:
1.54 atm
Explanation:
By Dalton's Law Of partial pressure,
Total Pressure = Sum of all partial pressures
So,P= P1 + P2 + P3
Therefore, P=0.23+0.42+0.89
=1.54 atm
Answer:
Option A. 1.14L
Explanation:
Data obtained from the question include:
V1 = 1.20 L
P1 = at stp = 760torr
T1 = at stp = 273K
P2 = 900torr
T2 = 35°C = 35 + 273 = 308K
V2 =?
Using P1V1/T1 = P2V2/T2, we can obtain the new volume as follows:
P1V1/T1 = P2V2/T2
(760 x 1.2)/273 = (900 x V2) /308
Cross multiply to express in linear form
273 x 900 x V2 = 760 x 1.2 x 308
Divide both side by 273 x 900
V2 = (760 x 1.2 x 308) /(273 x 900)
V2 = 1.14L