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3 years ago

Which quantum number distinguishes the different shapes of the orbitals?

1 answer:

7 0

The four quantum numbers are:
principle quantum number: this number describes the energy of orbitals. It describes the most probable distance between the electron and the nucleus.
angular quantum number: this number describes the shape of orbitals, and thus, describes the angular distribution.
magnetic quantum number: this number describes the number of orbitals and how they are oriented within the subshell
spin quantum number: this number determines the direction of the spin of the electron.

Based on the above, the quantum number that distinguishes the different shapes of the orbitals is the angular quantum number

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How many atoms of oxygen in the chemical formula 2Ca(ClO2)2?

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Answer:

Calcium Nitrate is made up of three different elements and contains a total of nine atoms. This compound's formula is Ca(NO3)2. There is one calcium atom, two nitrogen atoms, and there are six oxygen atoms in calcium nitrate

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3 years ago

In a water molecule (H2O), the oxygen atom has two unshared pairs of electrons and two bonding pairs of electrons. How do the un

vladimir1956 [14]

Answer:

They reduce the bond angle to be slightly lower than the tetrahedral bond angle, approximately 104.45 degrees.

Explanation:

The unshared pair of electrons or lone pair electrons in order to have the minimum repulsion possible with each other pushes the other bonding pairs closer together making the bond angle smaller or bent.

The bond angle is slightly lower than the tetrahedral bond angle of 108 degrees, leaving the water molecule with a bent molecular geometry.

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3 years ago

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the answer is option D "people emphasized obtaining knowledge through scientific experiments" (on plato)

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3 years ago

. the density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v). densit

ale4655 [162]

Density is intensive because it is the ratio of two extensive properties that is mass to volume.

<h3>What is Density ?</h3>

Density is defined as mass per unit volume. S.I unit if density is kg/m³.

It is expressed as

Density = $\frac{\text{Mass}}{\text{Volume}}$ or $d = \frac{m}{V}$

<h3>What is Intensive Property ? </h3>

Intensive property is the property which does not depend on the size of the system. Intensive property can be easily identified. Intensive property is the independent property. The size does not change in this.

Example of intensive property are Density, Freezing point, melting point, colour, Lustre, etc.

<h3>What is Extensive property ?</h3>

Extensive property is the property which depend on the substance. Extensive property cannot be easily identified.

Example of extensive property length, weight, volume, mass etc.

Thus from the above conclusion we can say that Density is intensive because it is the ratio of two extensive properties that is mass to volume.

Learn more about Density here: brainly.com/question/1354972

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Disclaimer: The given question is incomplete on the portal. Here is the complete question.

Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)

density = $\frac{\text{Mass}}{\text{Volume}}$ or $d = \frac{m}{V}$

Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.

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2 years ago

If a car is traveling 100 km/h and comes to a stop in 3 minutes,what is acceleration of a passenger who is using vehicle restrai

Rama09 [41]

We are given –

Final velocity of car is, v= 0
Initial velocity of car is, u= 100 km/hr
Time taken, t is = 3 minutes or 180 sec

Here–

$\qquad$ $\pink{\bf \longrightarrow Initial\: velocity = 100 \:km/hr}$

$\qquad$ $\sf \longrightarrow Initial\: velocity = \dfrac{ 100 \times 1000}{3600} \:m/s$

$\qquad$ $\pink{ \bf \longrightarrow Initial\: velocity = 27.78\: m/s}$

Now –

$\qquad$ ____________________________

$\qquad$ $\purple{\bf \longrightarrow Acceleration = \dfrac{Final\: Velocity -Initial \:Velocity }{Time}}$

$\qquad$ $\purple{\bf \longrightarrow Acceleration = \dfrac{v -u}{t}}$

$\qquad$ $\sf \longrightarrow Acceleration = \dfrac{(0- 27.78)}{1800}$

$\qquad$ $\sf \longrightarrow Acceleration =\cancel{ \dfrac{- 27.78}{1800}}$

$\qquad$ $\purple{\bf \longrightarrow Acceleration = -0.15 \: m/s^2}$

$\qquad$ _______________________________

6 0

2 years ago