Work = Force x distance
(10 pounds)(2 feet)
Work = 20 foot-pounds of work
hope this helps :)
Answer:
According to the travellers, Alpha Centauri is <em>c) very slightly less than 4 light-years</em>
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Explanation:
For a stationary observer, Alpha Centauri is 4 light-years away but for an observer who is travelling close to the speed of light, Alpha Centauri is <em>very slightly less than 4 light-years. </em>The following expression explains why:
v = d / t
where
- v is the speed of the spaceship
- d is the distance
- t is the time
Therefore,
d = v × t
d = (0.999 c)(4 light-years)
d = 3.996 light-years
This distance is<em> very slightly less than 4 light-years. </em>
4/3 m/s ( approximately 1.3333... m/s)
Answer:
The answer is D
Explanation:
I'm too lz to explain everything.
sorry.
Answer:
a. 4.9 m
Explanation:
To solve this problem we must take into account that power is defined as the relationship between the work and the time in which the work is done.
P = W/t
where:
P = power = 95 [W] (units of watts)
W = work [J] (units of Joules)
t = time = 6.2 [s]
We can clear the work from the previous equation.
W = P*t
W = 95*6.2 = 589 [J]
Now we know that the work is defined by the product of the force by the distance, therefore we can express the work done with the following equation.
W = F*d
where:
F = force = 120 [N] (units of Newtons)
d = distance [m]
d = W/F
d = 589/120
d = 4.9 [m]
