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3 years ago

The force that keeps objects moving in a circle is called centrifugal force. True False

Physics

2 answers:

Whitepunk [10]3 years ago

6 0

Answer:

The force that keeps objects moving in a circle is called centrifugal force. FALSE.

Explanation:

The force that keeps objects moving in a circle path is called centripetal force. It foes this by pulling the object into the center of the circle

Doss [256]3 years ago

3 0

Answer: False

Explanation:

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gregori [183]

Answer:

1.Nitrification happens when soil organisms change over ammonium into nitrate. Much of the cover between the carbon cycle and the nitrogen cycle happens within the soil, in forms conducted by soil organisms. Organisms break down supplements, construct modern compounds for their possess development, and inevitably pass on.

The second question im not sure sorry- the positive and negative one ;(

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4. Carbon makes its way through living things as carbon-based compounds, like vitality particles, fats and proteins, in the long run cycling its way back into the environment. Nitrogen is basically found within the air as well and enters the environments as supplements for plants. Water, nitrogen and carbon cycles. Carbon moves from the air and back by means of creatures and plants. Nitrogen moves from the environment and back by means of living beings. Water moves on, over, or underneath the surface of the Soil.

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3 0

3 years ago

A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturi

Darina [25.2K]

Answer: P = 36.75W

The additional power needed to account for the loss is 36.75W.

Explanation:

Given;

Mass of the runner m= 60 kg

Height of the centre of gravity h= 0.5m

Acceleration due to gravity g= 9.8m/s

The potential energy of the body for each step is;

P.E = mgh

P.E = 60 × 9.8 × 0.5

PE = 294J

Since the average loss per compression on the leg is 10%.

Energy loss = 10% (P.E)

E = 10% of 294J

E = 29.4J

To calculate the runner's additional power

given that time per stride is = 0.8s

Power P = Energy/time

P = E/t

P = 29.4J/0.8s

P = 36.75W

5 0

3 years ago

Significant digits show the _____ of measurements and calculations.

SashulF [63]

Significant digits show the precision of measurements and calculations

7 0

3 years ago

Convert the following to relative uncertainties <br>a) 2.70 ± 0.05cm<br>b) 12.02 ± 0.08cm

DENIUS [597]

data which is expressed in form of following way

$a = a_o + \Delta a$

here in above expression

$a_o$ = true value

$\Delta a$ = uncertainty in the value

now the relative uncertainty is given as

$\frac{\Delta a}{a_o}$

now by above formula we can say

a) 2.70 ± 0.05cm

here

True value = 2.70

uncertainty = 0.05

Relative uncertainty = $\frac{0.05}{2.70}$ = 0.0185

b) 12.02 ± 0.08cm

here

True value = 12.02

uncertainty = 0.08

Relative uncertainty = $\frac{0.08}{12.02}$ = 0.00665

4 0

3 years ago

Telephone signals are often transmitted over long distances by microwaves. What is the frequency of microwave radiation with a w

amm1812

Answer:

1) f= 8.6 GHz

2) t= 0.2 ms

Explanation:

Since microwaves are electromagnetic waves, they move at the same speed as the light in vacuum, i.e. 3*10⁸ m/s.
There exists a fixed relationship between the frequency (f) , the wavelength (λ) and the propagation speed in any wave, as follows:

$v = \lambda * f (1)$

Replacing by the givens, and solving for f, we get:

$f =\frac{c}{\lambda} =\frac{3e8m/s}{0.035m} = 8.57e9 Hz (2)$

⇒ f = 8.6 Ghz (with two significative figures)

Assuming that the microwaves travel at a constant speed in a straight line (behaving like rays) , we can apply the definition of average velocity, as follows:

$v =\frac{d}{t} (3)$

where v= c= speed of light in vacuum = 3*10⁸ m/s

d= distance between mountaintops = 52 km = 52*10³ m

Solving for t, we get:

$t = \frac{d}{c} = \frac{52e3m}{3e8m/s} = 17.3e-5 sec = 0.173e-3 sec = 0.173 ms (4)$

⇒ t = 0.2 ms (with two significative figures)

6 0

3 years ago