Let's think about the meaning of k, the spring's constant. Hooks law states:
![F=-kx](https://tex.z-dn.net/?f=F%3D-kx)
or, rewriting it:
![k= -\frac{F}{x}](https://tex.z-dn.net/?f=k%3D%20-%5Cfrac%7BF%7D%7Bx%7D%20)
where F is the force applied by the spring when we compress/release it of a certain amount of displacement x.
As we can see from the formula, the higher the value of k, the stronger is the force of the spring when we compress it of a certain fixed value x, so it will be more difficult to compress it with respect to a spring with smaller k. This means that the higher k, the stiffer is the spring.
When the ball leaves your hand, it has kinetic energy.
Kinetic energy = (1/2) (mass) (speed)²
= (1/2) (20kg) (5 m/sec)²
= 50 joules .
If the ball is not carrying solar panels or a jet engine, then it can
never have any MORE energy than that. And if, as we always
assume, it doesn't suffer any air resistance, then it won't LOSE
any energy. It has 50 joules of energy, permanently or until it hits
something.
If you toss it straight up, then it keeps climbing until it runs out of
kinetic energy. That is, its kinetic energy gets converted to potential
energy as it goes higher and slower. At the top, where it stops
momentarily and has no kinetic energy at all, all the energy it has
is potential energy ... the entire 50 joules you gave it with your toss.
They tend to be lustrous, ductile, malleable, and good conductors of electricity, while nonmetals are generally brittle (for solid nonmetals), lack lustre, and are insulators.
Answer:
A = [m/s]
B = [m/s²]
Explanation:
Assuming that V has SI units of m/s, then A and BT must also have units of m/s.
A = [m/s]
BT = [m/s]
Since T has SI units of s:
B [s] = [m/s]
B = [m/s²]