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Snezhnost [94]
3 years ago
6

Driving along a crowded freeway, you notice that it takes a time t to go from one mile marker to the next. When you increase you

r speed by 8.2 mi/h , the time to go one mile decreases by 12 s . what is your original speed?
Physics
2 answers:
Finger [1]3 years ago
6 0
<h3>Answer:</h3>

Your original speed was 45.668 mph.

<h3>Explanation:</h3>

To find seconds per mile, divide 3600 by speed in miles per hour. Let x represent the original speed. Then 3600/x is the original time per mile.

The new time per mile is 3600/(x +8.2), and that is 12 seconds less than the original time per mile:

... 3600/(x +8.2) = 3600/x -12

Multiplying by the product of the denominators, we have ...

... 3600(x) = 3600(x +8.2) -12(x)(x +8.2)

Dividing by 12 and putting this into standard form, we have

... x^2 +8.2x -300(8.2) = 0

... x = (-8.2 +√(8.2² -4(-300·8.2)))/2 = -4.1 +√2476.81 . . . . solved using the quadratic formula

... x ≈ 45.6676 . . . mi/h

Your original speed was about 45.67 mph.

_____

<em>Check</em>

Your original time per mile was about 3600/45.66756 ≈ 78.8306 seconds. Your shorter time per mile is about 3600/53.86756 ≈ 66.8306 seconds, which is 12 seconds less.

djverab [1.8K]3 years ago
5 0
From the first condition
1 = vo t

From the second condition
1 = 8.2 (t - 12/60)

The time it takes to travel 1 mile in the second condition is
t = 0.32 hr

The original speed is
1 = vo (0.32)
vo = 3.13 mi/h
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Given that: α (t) = (6.0 rad/s4)t² = 6t² rad/s⁴. Hence:

θ(t) = ∫∫α(t) dtdt

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θ(t) = ∫[2t³]dt = t⁴/2 rad

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t = 3.348 s

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An ambulance with a siren emitting a whine at 1790 Hz overtakes and passes a cyclist pedaling a bike at 2.36 m/s. After being pa
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let the velocity of the ambulance be 'vₓ'

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