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olya-2409 [2.1K]
3 years ago
7

What happens during nuclear decay? Put these events in order to describe the process, start to finish. The nucleus starts to fal

l apart. Radiation, mass, and energy are released. The nucleus is unstable. The nucleus is stable.
Physics
2 answers:
Liula [17]3 years ago
8 0

In a nuclear decay, an unstable atom releases energy or particles to reach a more stable state. The energy released is equivalent to the difference between the mass of the original atom and the resultant atom and particles.

The events involved in the decay arranged in order to describe the process:

1. The nucleus is unstable.

2. The nucleus start to fall apart.

3. Radiation, mass, and energy are released.

4. The nucleus is stable.

BARSIC [14]3 years ago
3 0
The nucleus is unstable
The nucleus strts to fall apart
Radiation,mass and energy are released
The nucleus is stable
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Which of the following is the best reason for using a scanning electron microscope?
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Answer is C: Ability to see three-dimensional images of the surfaces of object

Explanation:

To enable the technician see fractures and broken particles in a better resolution as the SEM sees the peaks and valley of the structure.

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A rugby player passes the ball 7.88 m across the field, where it is caught at the same height as it left his hand. (Assume the p
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Explanation:

Given

Range of ball =7.88 m

Initial speed=13.1 m/s

and we know

Range of Projectile is

R=\frac{u^2sin2\theta }{g}

13.1=\frac{13.1^2\times sin2\theta }{9.8}

7.88\times 9.8=13.1^2\times sin2\theta

sin2\theta =0.4499

2\theta =26.74^{\circ}

\theta =13.37 ^{\circ}

(b)other angle would be complementary of \theta

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3 years ago
How much force is required to accelerate a 12 kg mass at 5 m/s 2
Savatey [412]

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60 N

Explanation:

This is just Newton's Second Law

F = m*a

F = ?

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4 0
2 years ago
A positively charged object is placed to the left of a negatively charged object. (PLS HELP)
liberstina [14]
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3 years ago
Read 2 more answers
In a certain region of space near earth's surface, a uniform horizontal magnetic field of magnitude B exists above a level defin
dmitriy555 [2]

Answer:

a) F = \frac{\pi d^2B^2lv}{16p}  

b) attached below

c) 0.037 m/s

Explanation:

<u>a) Determine the magnetic "drag" force acting  at the moment </u>

speed = v

first step: determine current in the loop

I = \frac{\pi d^2}{16pl} B lv   ----- ( 1 )

given that the current will induce force on the three sides of the loop found in the magnetic field

forces on vertical sides = + opposite

we will cancel out

hence equation 1 becomes

F = \frac{\pi d^2B^2lv}{16p}   ( according to Lenz law we can say that the direction of force is upwards and this force will slow down the decrease in flux )

<u>b) Determine the formula for Vt</u>

attached below

<u>c) Find Vt </u>

given :

B = 0.80 T

density of copper = 8.9 * 10^3 kg/m^3

resistivity of copper = 1.68 * 10^-8 Ωm

∴ Vt = 16 ( 8.9 * 10^3 kg/m^3 ) ( 1.68 * 10^-8 Ωm ) ( 9.8 m/s^2 ) / ( 0.08 T)^2

       = 0.037 m/s

3 0
3 years ago
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