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Nana76 [90]
2 years ago
13

plan a controlled experiment to investigate how changing the net force on an object changes its acceleration. The mass of the ob

ject must stay the same.
Physics
2 answers:
ahrayia [7]2 years ago
7 0

Answer:

e

Explanation:

True [87]2 years ago
4 0
Force increases as speed increases
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A block slides down a rough ramp with a 30-degree incline as shown.
In-s [12.5K]

Answer:

Image 4 ?

Explanation:

5 0
3 years ago
Which of these processes are chemical reactions
White raven [17]

Explanation:

  • In chemical reactions, chemical changes occur.
  • Atoms are simply rearranged and new bonds are formed.
  • Chemical reactions are driven by a need for atoms to attain stability in their structure.
  • In all chemical reactions, a reactant or reactants gives new product i.e new substances are formed.
  • Most these reactions are not easily reversible.
  • They are usually accompanied by the release of energy.

Learn more:

Chemical change brainly.com/question/9388643

#learnwithBrainly

5 0
3 years ago
How can you tell if an igneous rock has an intrusive or extrusive origin?
wariber [46]

Intrusive igneous rocks cool down from magma slowly because they form underneath the surface, that will make them have large crystals.

Extrusive igneous rocks cool down from lava rapidly because they form at the surface, so that will make them have small crystals.

4 0
2 years ago
An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 25 m lower vert
Musya8 [376]

Answer:

x = 5.79 m

Explanation:

given,

mass of the car = 39000 Kg

spring constant = 5.7 x 10⁵ N/m

acceleration due to gravity = 9.8 m/s²

height of the track = 25 m

length of spring compressed = ?

using conservation of energy

potential energy is converted into spring energy

m g h = \dfrac{1}{2}kx^2

x =\sqrt{\dfrac{2 m g h}{k}}

x =\sqrt{\dfrac{2\times 39000 \times 9.8 \times 25}{5.7 \times 10^{5}}}

x =\sqrt{33.5263}

x = 5.79 m

the spring is compressed to x = 5.79 m to stop the car.

3 0
3 years ago
car is moving at 40 m/s. At 10 meters the driver spots a deer on the road and instantly steps on the brakes. If the car is 400 k
Mice21 [21]

Answer:

32000 N

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 40 m/s

Distance (s) = 10 m

Final velocity (v) = 0 m/s

Mass (m) of car = 400 Kg

Force (F) =?

Next, we shall determine the acceleration of the the car. This can be obtained as follow:

Initial velocity (u) = 40 m/s

Distance (s) = 10 m

Final velocity (v) = 0 m/s

Acceleration (a) =?

v² = u² + 2as

0² = 40² + (2 × a × 10)

0 = 1600 + 20a

Collect like terms

0 – 1600 = 20a

–1600 = 20a

Divide both side by –1600

a = –1600 / 20

a = –80 m/s²

The negative sign indicate that the car is decelerating i.e coming to rest.

Finally, we shall determine the force needed to stop the car. This can be obtained as follow:

Mass (m) of car = 400 Kg

Acceleration (a) = –80 m/s²

Force (F) =?

F = ma

F = 400 × –80

F = – 32000 N

NOTE: The negative sign indicate that the force is in opposite direction to the motion of the car.

7 0
2 years ago
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