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HACTEHA [7]
3 years ago
6

A net force of 20 N acting on a wooden block produces an

Physics
1 answer:
Ymorist [56]3 years ago
5 0

Answer:

From the second law of motion:

F = ma

we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s

So, F=  20N   and  a = 4 m/s/s

Replacing the variables in the equation:

20 = 4* m

m = 20 / 4

m = 5 kg

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A 5cm tall object is placed 4cm in front of a converging lens that has a focal length of 8cm. Where is the image located in ____
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Answer:

a. -8 cm

Explanation:

d_{o} = distance of the object = 4 cm

d_{i} = distance of the image = ?

f = focal length of the converging lens  = 8 cm

using the lens equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}

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4 0
3 years ago
Joanne drives her car at a speed of 20 m/s. when she applied her breaks, a frictional force of 2000 N brought her car to a compl
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Answer:

A) 1000 kg

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1 year ago
Kinetic energy problemset
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3 years ago
) A 1000 kg car travelling at 50 m/s slams into a 1500 kg parked truck in an inelastic manner as
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(a)

KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J


(b)

The energy is entirely dissipated by the force of friction in the brake system.


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W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J



(d)

Fd = delta KE

F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N

The magnitude of the friction force is 4800 N.
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