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2 years ago

5

Hilda plans to display in a clear cube the needle betsy ross used to sew the first american flag. the needle will fit exactly as

the diagonal of the cube. if the side length of the clear cube is startroot 3 endroot inches, and the diagonal of a face of the cube is startroot 6 endroot inches, what is the length of the needle? startroot 6 endroot inches 3 inches 3 startroot 2 endroot inches 6 inches

2 answers:

inysia [295]2 years ago

8 0

Based on the length of side of the cube given, the length of the needle is 2.28 inches.

<h3>What is the length of the needle?</h3>

The length of the side of a cube and its diagonal are related by the formula below:

$Length \: of \: Diagonal = \sqrt{3s}$

where s is length of side

$Side \: Length \: of \: the \: Cube = \sqrt{3inches}$

$Diagonal \: of \: a \: face \: of \: the \: cube = \sqrt{6inches}$

$The \: length \: of \: the \: needle = \sqrt{3\sqrt{3}} = 2.28 \: inches \\$

Therefore, the length of the needle is 2.28 inches

Learn more about length of diagonal of cube at: brainly.com/question/800212

#SPJ4

Irina-Kira [14]2 years ago

7 0

Answer:

Its B 3in

Explanation:

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4 years ago

A school bus has a mass (including the driver and passengers) of 1.64 times 10^4 kg and is driving north at a speed of 15.2 km/h

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Answer:

Explanation:

Given

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Momentum of North moving bus

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$P_1=1.6\times 10^4\times 4.22$

$P_1=6.768\times 10^4 kg-m/s$

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$P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38$

For total momentum to be towards south

$P_2-P_1$ should be greater than 0

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$P_2=P_1$

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3 years ago

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Answer:

I'm not sure..but please refer to your teacher later.

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3 years ago

Read 2 more answers

At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial

elena55 [62]

Answer : The partial pressure of $SO_3$ is, 67.009 atm

Solution : Given,

Partial pressure of $SO_2$ at equilibrium = 30.6 atm

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The given balanced equilibrium reaction is,

$2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}$

Now put all the values of partial pressure, we get

$0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}$

$p_{SO_3}=67.009atm$

Therefore, the partial pressure of $SO_3$ is, 67.009 atm

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