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1 year ago

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Hilda plans to display in a clear cube the needle betsy ross used to sew the first american flag. the needle will fit exactly as

the diagonal of the cube. if the side length of the clear cube is startroot 3 endroot inches, and the diagonal of a face of the cube is startroot 6 endroot inches, what is the length of the needle? startroot 6 endroot inches 3 inches 3 startroot 2 endroot inches 6 inches

2 answers:

inysia [295]1 year ago

8 0

Based on the length of side of the cube given, the length of the needle is 2.28 inches.

<h3>What is the length of the needle?</h3>

The length of the side of a cube and its diagonal are related by the formula below:

$Length \: of \: Diagonal = \sqrt{3s}$

where s is length of side

$Side \: Length \: of \: the \: Cube = \sqrt{3inches}$

$Diagonal \: of \: a \: face \: of \: the \: cube = \sqrt{6inches}$

$The \: length \: of \: the \: needle = \sqrt{3\sqrt{3}} = 2.28 \: inches \\$

Therefore, the length of the needle is 2.28 inches

Learn more about length of diagonal of cube at: brainly.com/question/800212

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Irina-Kira [14]1 year ago

7 0

Answer:

Its B 3in

Explanation:

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topjm [15]

Answer:

When uranium is mined, it consists of approximately 99.3% uranium-238 (U238), 0.7% uranium-235 (U235), and < 0.01% uranium-234 (U234). These are the different uranium isotopes. Isotopes of uranium contain 92 protons in the atom's center or nucleus. (The number of protons in the nucleus is what makes the atoms "uranium.") The U238 atoms contain 146 neutrons, the U235 atoms contain 143 neutrons, and the U234 atoms contain only 142 neutrons. The total number of protons plus neutrons gives the atomic mass of each isotope — that is 238, 235, or 234, respectively. On an atomic level, the size and weight of these isotopes are slightly different. This implies that with the right equipment and under the right conditions, the isotopes can be separated.

Explanation:

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1 year ago

MathPhys Help pls Tysm

HACTEHA [7]

Answer:

8.75

Explanation:

First, find the force of friction.

Kinetic energy = work done by friction

½ mv² = Fd

½ (3.9 kg) (2.9 m/s)² = F (1.4 m)

F = 11.7 N

Next, find the distance at the new velocity.

Kinetic energy = work done by friction

½ mv² = Fd

½ (3.9 kg) (2.5 × 2.9 m/s)² = (11.7 N) d

d = 8.75 m

3 0

2 years ago

Read 2 more answers

Which is the currrent SI unit to use in measuring the amount of material contained in a solid sphere

olya-2409 [2.1K]

Hey

SI unit for measure the amount of material contained in a solid sphere metre cube(m^3).

mean it have Volume .

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2 years ago

If I connect an inductor (L) to a capacitor (C), I will get an LC oscillator circuit with some natural frequency omega. If I wer

mart [117]

The new natural frequency would be ω/2.

we know that,

$f = \frac{1}{2 pi \sqrt{LC} }$ = ω. -> equation 1

now, when capacitance is quadrupled,

$f' = \frac{1}{2 pi \sqrt{L ( 4C )} }$

$f' = \frac{1}{2 pi (2)\sqrt{LC} }$ . -> equation 2

substituting value of equation 1 in equation 2 , we get,

$f' = \frac{w}{2}$

Hence, the new natural frequency of the circuit is ω/2.

what do you mean by frequency ?

The resonant frequency for a particular circuit is the frequency at which this equality stands true. Where L is the inductance in henries and C is the capacitance in farads, this is the LC circuit's resonant frequency.

Learn more about frequency here:-

brainly.com/question/12530980

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8 0

1 year ago

A ball is thrown vertically downwards with a speed 7.3 m/s from the top of a 51 m tall building. With what speed will it hit the

ddd [48]

Answer:

32.46m/s

Explanation:

Hello,

To solve this exercise we must be clear that the ball moves with constant acceleration with the value of gravity = 9.81m / S ^ 2

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are the follow

$\frac {Vf^{2}-Vo^2}{2.a} =X$

Where

Vf = final speed

Vo = Initial speed =7.3m/S

A = g=acceleration =9.81m/s^2

X = displacement =51m}

solving for Vf

$Vf=\sqrt{Vo^2+2gX}\\Vf=\sqrt{7.3^2+2(9.81)(51)}=32.46m/s$

the speed with the ball hits the ground is 32.46m/s

8 0

2 years ago

Read 2 more answers