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navik [9.2K]
3 years ago
15

In a device like the one shown below, the cylinder is allowed to fall a distance of 300 m. As a result, the temperature of the w

ater increases by 2.7°C. What would have been the increase in temperature if the cylinder were only allowed to fall 100 m?
Physics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

Increase in the temperature of water would be 0.9 degree C

Explanation:

As we know by energy conservation

Change in the gravitational potential energy of the cylinder = increase in the thermal energy of the water

Here we know that the gravitational potential energy of the cylinder is given as

U = mgh

here we have

h = 300 m

now we can say

Mc\Delta T = (m \times 9.8 \times 300)

now if the cylinder falls from height h = 100 m

then we have

Mc\Delta T' = (m \times 9.8 \times 100)

now from above two equations

\frac{\Delta T'}{\Delta T} = \frac{100}{300}

\Delta T' = 2.7 \times \frac{1}{3} = 0.9 Degree C

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